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Solution :

(i) `3x^2-5x+2=0` <br>
`= 3x^2 -3x - 2x +2=0` <br>
`= 3x(x-1)-2(x-1)=0` <br>
`=(3x-2)(x-1)=0` <br>
`x = 2/3 , 1 ` <br>
(ii) `x^2+4x+5=0` <br>
`D= b^2 - 4ac = (4)^2 -(4)(1)(5)` <br>
` = 16- 20 =-4` <br>
`x= (-b+- sqrt D)/(2a)` <br>
`= (-4 +- 2i)/2 = -2+-i` <br>
(iii) `2x^2 - 2 sqrt2 x +1 = 0` <br>
`D= b^2 - 4ac` <br>
`= (-2 sqrt2)^2 - 4(2)(1)` <br>
`= 8-8 = 0` <br>
`x = -b/(2a) = -(-2 sqrt2)/(2(2)) ` <br>
`=1/sqrt2` <br>
answer
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