SOLUTION

For a transistor, the base current, the emitter current, and the collector current are related as:

I_E = I_B + I_C

where I_C = β I_B

β = Current gain of the transistor

From the given figure, Apply KVL

10 – I_B× R_B – V_BE = 0

Let us assume V_BE = 0.7 V

10 – I_B (1× 10⁶) – 0.7 = 0

I_B = 9.3 μA

We know that,

I_C = β I_B

Where,

I_C  & I_B = collector current and base current

Therefore,

I_C = 100 × 9.3 μA

= 930 μA

= 0.93 mA

≈ 1 mA