Arithmetic Operations for Image Enhancement MCQ [Free PDF] – Objective Question Answer for Arithmetic Operations for Image Enhancement Quiz

11. The Laplacian is which of the following operator?

A. Nonlinear operator
B. Order-Statistic operator
C. Linear operator
D. None of the mentioned

Answer: C

Derivatives of any order are linear operations and since Laplacian is the simplest isotropic derivative operator, so is a linear operator.
Order-Statistics operators are nonlinear operators.

 

12. A Laplacian for an image f(x, y) is defined as:   is given by ________

A. [f(x + 1, y) + f(x – 1, y) – 2f(x, y)] and [f(x, y + 1) + f(x, y – 1) – 2f(x, y)] respectively
B. [f(x + 1, y + 1) + f(x, y – 1) – 2f(x, y)] and [f(x , y + 1) + f(x – 1, y) – 2f(x, y)] respectively
C. [f(x, y + 1) + f(x, y – 1) – 2f(x, y)] and [f(x + 1, y) + f(x – 1, y) – 2f(x, y)] respectively
D. None of the mentioned

Answer: A

For a Laplacian given by:∇2 f=
Applying second order derivative in x direction (∂2 f)/∂x2 = [f(x + 1, y) + f(x – 1, y) – 2f(x, y)], and
Applying second order derivative in y direction (∂2 f)/∂y2 = [f(x, y + 1) + f(x, y – 1) – 2f(x, y)].

 

13. The Laplacian ∇2 f=[f(x + 1, y) + f(x – 1, y) + f(x, y + 1) + f(x, y – 1) – 4f(x, y)], gives an isotropic result for rotations in increment by what degree?

A. 90o
B. 0o
C. 45o
D. None of the mentioned

Answer: A

The given Laplacian gives isotropic results for 90o incremental rotations.

 

14. The Laplacian incorporated with diagonal directions, i.e. ∇2 f=[f(x + 1, y) + f(x – 1, y) + f(x, y + 1) + f(x, y – 1) – 8f(x, y)], gives an isotropic result for rotations in increment by what degree?

A. 90o
B. 0o
C. 45o
D. None of the mentioned

Answer: A

The given Laplacian since includes the diagonal direction, so, gives an isotropic result for 45o incremental rotations.

 

15. Applying Laplacian has which of the following result(s)?

A. Produces images having greyish edge lines
B. Produces image having a featureless background
C. All of the mentioned
D. None of the mentioned

Answer: C

Since Laplacian is a derivative operator, so, highlights the gray-level discontinuities in an image and deemphasizes areas with slowly varying gray levels. Hence, produces images having greyish edge lines superimposed on the featureless background.

 

16. Applying Laplacian produces an image having featureless background which is recovered maintaining the sharpness of the Laplacian operation by either adding or subtracting it from the original image depending upon the Laplacian definition used. Which of the following is true based on the above statement?

A. If the definition used has a negative center coefficient, then subtraction is done
B. If the definition used has a positive center coefficient, then subtraction is done
C. If the definition used has a negative center coefficient, then the addition is done
D. None of the mentioned

Answer: A

Applying Laplacian produces an image having featureless background which is recovered maintaining the sharpness of the Laplacian operation using the original image either added if the Laplacian definition used has a positive center coefficient or subtracting the result from the original image if has a negative center coefficient.

 

17. A mask of size 3*3 is formed using Laplacian including diagonal neighbors that have a central coefficient of 9. Then, what would be the central coefficient of the same mask if it is made without diagonal neighbors?

A. 5
B. -5
C. 8
D. -8

Answer: A

The mask is formed by eliminating diagonal neighbors i.e. 4f(x, y) since each diagonal contains a -2f(x, y), the mask has 5 as its central coefficient.

 

18. Which of the following mask(s) is/are used to sharpen images by subtracting a blurred version of the original image from the original image itself?

A. Unsharp mask
B. High-boost filter
C. All of the mentioned
D. None of the mentioned

Answer: C

Unsharp mask sharpens images by subtracting a blurred version of the original image from the original image itself.
A high-boost filter is a generalized form of unsharp mask.

 

19. Which of the following gives an expression for a high boost filtered image file, if f represents an image, f blurred version off, fs unsharp mask filtered image, and A ≥ 1?

A. fhb = (A – 1) f(x, y) + f(x, y) – f x, y)
B. fhb = A f(x, y) – f(x,y)
C. fhb = (A – 1) f(x, y) + fs(x, y)
D. All of the mentioned

Answer: D

A high-boost filter is a generalized form of unsharp mask and is given by:
fhb = A f(x, y) – f (x, y)
Or, fhb = (A – 1) f(x, y) + f(x, y) – f(x, y), that can be written as
fhb = (A – 1) f(x, y) + fs(x, y), where fs(x, y) = f(x, y) – f (x, y).

 

20. If we use a Laplacian to obtain a sharp image for unsharp mask filtered image fs(x, y) of f(x, y) as the input image, and if the center coefficient of the Laplacian mask is negative then, which of the following expression gives the high boost filtered image fhb, if ∇2 f represent Laplacian?

A. fhb = A f(x, y) – ∇2 f(x,y)
B. fhb = A f(x, y) + ∇2 f(x,y)
C. fhb = ∇2 f(x,y)
D. None of the mentioned

Answer: A

If Laplacian is used to obtain a sharp image for an unsharp mask filtered image, then

fhb = A f(x, y) – ∇2 f(x,y)

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