At a particular unbalanced node, the real powers specified are Leaving the node 20 MW, 25 MW

At a particular unbalanced node, the real powers specified are Leaving the node 20 MW, 25 MW Entering the node 60 MW, 30 MW Then the balanced power will be

Right Answer is:

45 MW leaving the node

SOLUTION

According to Kirchhoff’s current law (KCL) at any node (junction) in an electrical circuit, the sum of currents flowing into that node is equal to the sum of currents flowing out of that node.

Sum of power entering the node 60 + 30 =90 MW
Sum of power leaving the node 20 + 25 = 45

To make the node balance

Entering the Node = Leaving the Node

Enetering the Node = 90 MW

Leaving the Node = 45 MW

To make the power flow balanced sum of power entering the node must be equal to the sum of power leaving the node. Hence the sum of power entering the node must be equal to 45 MW.

90 = 45 + 45 leaving the Node

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