# In a balanced acb sequence, phase a to neutral voltage is Van = 100∠20V. Line-to-line voltage Vac is given by

In a balanced acb sequence, phase a to neutral voltage is V

_{an}= 100∠20V. Line -to-line voltage V_{ac}is given by### Right Answer is:

V_{ac} = 100√3 ∠50V

#### SOLUTION

The phase sequence is called a positive sequence or abc sequence when V_{an} leads V_{bn} by 120° and V_{bn} leads V_{cn }by 120°. Line to line voltage V_{an} leads phase voltage V_{a} by 30°.

The phase sequence is called a negative sequence or acb sequence when V_{an} leads V_{cn} by 120° and V_{cn} leads V_{bn }by 120°. The line to line voltage V_{an} lags phase voltage V_{a} by 30°.

For Negative Phase sequence ACB, the line to line voltage V_{ac} is given as

V_{ac} = √3V_{an}∠−150°

V_{ac} = √3(100V∠20°) × (1∠−150°)

V_{ac} = 100√3∠−130°

or

**V _{ac} = 100√3∠50°**