# Capacitance of Multiplate Capacitor MCQ [Free PDF] – Objective Question Answer for Capacitance of Multiplate Capacitor Quiz

1. Which is the correct expression for the capacitance of a multi-plate capacitor?

A. C = absolute permittivity × A/d
B. C = Actual permittivity × (n-1) × A/d
C. C = Actual permittivity × (n) × A/d
D. Actual permittivity × (n+1) × A/d

The correct expression for capacitance of a multi plate capacitor is

C = Actual permittivity × (n-1) × A/d.

Where

n = number of plates
A = area of cross section of the plates
d = distance of separation between the plates.

2. What happens to the capacitance of a multi-plate capacitor when the area of a cross-section of the plate decreases?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

When the area of the cross-section decreases, the capacitance also decreases since it is related to the formula

C = Actual permittivity × (n-1) × A/d.

Here, we can see that the capacitance is directly proportional to the area of the cross-section.

3. What happens to the capacitance of a multi-plate capacitor when the distance of separation between the plate increases?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

When the distance of separation between the plates increases, the capacitance decreases since it is related to the formula

C = Actual permittivity × (n-1) × A/d.

Here, we can see that the capacitance is inversely proportional to the distance of separation.

4. What happens to the capacitance of a multi-plate capacitor when the number of plates increases?

A. Increases
B. Decreases
C. Remains constant
D. Becomes zero

When the number of capacitors increases, the capacitance also increases since it is related to the formula

C = Actual permittivity × (n-1) × A/d.

Here, we can see that the capacitance is directly proportional to the number of capacitors.

5. Find the capacitance of a multi-plate capacitor whose actual permittivity = 5F/m, n = 3, A = 4m2and d = 2m.

A. 10F
B. 20F
C. 30F
D. 40F

The formula for capacitance of a multi plate capacitor

C = Actual permittivity × (n-1) × A/d.

Thus, C = 5 × (3-1) × 4/2 = 20F.

6. Find the capacitance of a multi-plate capacitor whose relative permittivity = 5, n = 3, A = 4m2 and d = 2m.

A. 1.77 × 10-10 F
B. 1.77 × 1010 F
C. 1.77 × 10-11 F
D. 1.77 × 1011 F

The formula for capacitance of a multi plate capacitor

C = Relative permittivity × absolute permittivity × (n-1) × A/d.

C = 5 × 8.85 × 10-12 × (3-1) × 4/2 = 1.77 × 10-10.

7. Find the number of plates in the multi plate capacitor having C = 20F absolute permittivity = 5F/m, A = 4m2 and d = 2m.

A. 1
B. 2
C. 3
D. 4

The formula for capacitance of a multi plate capacitor:

C = Actual permittivity × (n-1) × A/d.

Substituting the given values in the equation, we get n = 3.

8. Calculate the distance between the plates of the capacitor having C = 20F, actual permittivity = 5F/m n = 3 and A = 4m2.

A. 1m
B. 2m
C. 3m
D. 4m

The formula for the capacitance of a multi-plate capacitor

C = Actual permittivity × (n-1) × A/d.

Substituting the given values in the equation, we get d = 2m.

9. Calculate the area of cross section of the multi plate capacitor having C = 20F, actual permittivity = 5F/m n = 3 and d = 2m.

A. 1m2
B. 2m2
C. 3m2
D. 4m2

The formula for the capacitance of a multi-plate capacitor

C = Actual permittivity × (n-1) × A/d.

Substituting the given values in the equation, we get A = 4m2.

10. Calculate the number of plates in the multi plate capacitor having C = 1.77 × 10-10F relative permittivity = 5, A = 4m2 and d = 2m.

A. 1
B. 2
C. 3
D. 4