# The corona loss on a particular system at 50 Hz is 1.2 kW/phase per km. The corona loss on the same system with supply frequency 60 Hz will be

The corona loss on a particular system at 50 Hz is 1.2 kW/phase per km. The corona loss on the same system with supply frequency 60 Hz will be

### Right Answer is: 1.36 kW/phase/kmPlease enable JavaScriptW = 1/2 CV^2 The equation above describes the amount of energy stored in a capacitor in joules, W, in terms C, the capacitance of the capacitor in farads, and V, the voltage in volts. Which of the following correctly gives C in terms of W and V?

#### SOLUTION

Given-

f= 50 Hz

f= 60 Hz

PL1 = 1.2 kW / km / phase

Corona Loss (PL) ∝ (f + 25)

$\begin{array}{l} \frac{{{P_2}}}{{{P_1}}} = \frac{{\left( {{f_2} + 25} \right)}}{{\left( {{f_1} + 25} \right)}}\\ \\ {P_2} = \frac{{60 + 25}}{{50 + 25}} \times {P_1} \end{array}$

P2 = 1.36 kW/phase/km

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