A current carrying conductor is wrapped eight times around the jaw of a clamp-on meter that reads 50 A . What will be the actual value of the conductor current?
Right Answer is:
Let, Np is a number of turn in the primary winding
Ns is the number of turns in the secondary winding.
Ip and Is are primary and secondary turns respectively.
Therefore, the secondary current is given by,
Is = (Ip × Np)/Ns
Np = 1,
Ns = 8,
Ip = 50 A
Is = (50 × 1)/8
Is = 6.25 A