If the current in the armature of the DC series motor is reduced to 5%, the torque of the motor will become:
If the current in the armature of the DC series motor is reduced to 5%, the torque of the motor will become:
Right Answer is:
25% of the Previous Value
SOLUTION
In DC series Motor, the torque is directly proportional to the square of the armature current
T ∝ Ia2
So if the armature current is reduced to 5% then torque is
T = 52
T = 25%