Discrete Time System Analysis MCQ Quiz – Objective Question with Answer for Discrete Time System Analysis

11. Is the system with impulse response h(n)=2nu(n-1) stable.

A. True
B. False

Answer: B

Let S=\(\sum_{n=-{\infty}}^{\infty}|h(n)|\)

=\(\sum_{n=-{\infty}}^{\infty}2^n u(n-1)\)

=\(\sum_{n=-{\infty}}^{\infty}2^n\)

=2+4+8+…=∞

So, the system is not stable.

 

11. If x(n) is a discrete-time signal, then the value of x(n) at the non-integer value of ‘n’ is?

A. Zero
B. Positive
C. Negative
D. Not defined

Answer: D

For a discrete-time signal, the value of x(n) exists only at integral values of n. So, for a non-integer value of ‘n’ the value of x(n) does not exist.

 

12. The discrete-time function defined as u(n)=n for n≥0;u(n)=0 for n<0 is an _____________

A. Unit sample signal
B. Unit step signal
C. Unit ramp signal
D. None of the mentioned

Answer: C

When we plot the graph for the given function, we get a straight line passing through the origin with a unit positive slope. So, the function is called a unit ramp signal.

 

13. The phase function of a discrete-time signal x(n)=an, where a=r.ejθ is?

A. tan(nθ)
B. nθ
C. tan-1(nθ)
D. none of the mentioned

Answer: B

Given x(n)=an=(r.ejθ)n = rn.ejnθ
=>x(n)=rn.(cosnθ+jsinnθ)
Phase function is tan-1(cosnθ/sinnθ)=tan-1(tan nθ)=nθ.

 

14. The signal given by the equation $\mathop \sum \limits_{n = – \infty }^\infty |x(n){|^2}$ is known as __________

A. Energy signal
B. Power signal
C. Work done signal
D. None of the mentioned

Answer: A

We have used the magnitude-squared values of x(n), so that our definition applies to complex-valued as well as real-valued signals. If the energy of the signal is finite i.e., 0<E<∞ then the given signal is known as the Energy signal.

 

15. x(n)*δ(n-k)=?

A. x(n)
B. x(k)
C. x(k)*δ(n-k)
D. x(k)*δ(k)

Answer: C

The given signal is defined only when n=k by the definition of delta function. So, x(n)*δ(n-k)= x(k)*δ(n-k).

 

16. A real valued signal x(n) is called as anti-symmetric if ___________

A. x(n)=x(-n)
B. x(n)=-x(-n)
C. x(n)=-x(n)
D. none of the mentioned

Answer: B

According to the definition of an anti-symmetric signal, the signal x(n) should be symmetric over origin. So, for the signal x(n) to be symmetric, it should satisfy the condition x(n)=-x(-n).

 

17. The odd part of a signal x(t) is?

A. x(t)+x(-t)
B. x(t)-x(-t)
C. (1/2)*(x(t)+x(-t))
D. (1/2)*(x(t)-x(-t))

Answer: D

Let x(t)=xe(t)+xo(t)
=>x(-t)=xe(-t)-xo(-t)
By subtracting the above two equations, we get
xo(t)=(1/2)*(x(t)-x(-t)).

 

18. Time scaling operation is also known as ___________

A. Down-sampling
B. Up-sampling
C. Sampling
D. None of the mentioned

Answer: A

If the signal x(n) was originally obtained by sampling a signal xa(t), then x(n)=xa(nT). Now, y(n)=x(2n)(say)=xa(2nT).

Hence the time scaling operation is equivalent to changing the sampling rate from 1/T to 1/2T, that is to decreasing the rate by a factor of 2. So, time scaling is also called down-sampling.

 

19. What is the condition for a signal x(n)=Brn where r=eαT to be called a decaying exponential signal?

A. 0<r<∞
B. 0<r<1
C. r>1
D. r<0

Answer: B

When the value of ‘r’ lies between 0 and 1 then the value of x(n) goes on decreasing exponentially with an increase in the value of ‘n’. So, the signal is called a decaying exponential signal.</r<1 </r<∞

20. The function given by the equation x(n)=1, for n=0; x(n)=0, for n≠0 is a _____________

A. Step function
B. Ramp function
C. Triangular function
D. Impulse function

Answer: D

According to the definition of the impulse function, it is defined only at n=0 and is not defined elsewhere which is as per the signal given.

 

21. The output signal when a signal x(n)=(0,1,2,3) is processed through an ‘Identical’ system is?

A. (3,2,1,0)
B. (1,2,3,0)
C. (0,1,2,3)
D. None of the mentioned

Answer: C

An identical system is a system whose output is the same as the input, that is it does not perform any operation on the input and transmits it.

22. If a signal x(n) is passed through a system to get an output signal of y(n)=x(n+1), then the signal is said to be ____________

A. Delayed
B. Advanced
C. No operation
D. None of the mentioned

Answer: D

For example, the value of the output at the time n=0 is y(0)=x(1), that is the system is advanced by one unit.

 

23. If the output of the system is \(y(n)=\sum_{k=-\infty}^nx(y)\) with an input of x(n) then the system will work as ___________

A. Accumulator
B. Adder
C. Subtractor
D. Multiplier

Answer: A

From the equation given, y(n)=x(n)+x(n-1)+x(n-2)+…. .This system calculates the running sum of all the past input values till the present time. So, it acts as an accumulator.

24. What is the output y(n) when a signal x(n)=n*u(n)is passed through an accumulator system under the conditions that it is initially relaxed?

A. \(\frac{n^2+n+1}{2}\)

B. \(\frac{n(n+1)}{2}\)

C. \(\frac{n^2+n+2}{2}\)

D. None of the mentioned

Answer: B

Given that the system is initially relaxed, that is y(-1)=0

According to the equation of the accumulator,

y(n)=\(∑_{k=-∞}^n x(n)\)

=\(∑_{k=-∞}^{-1} x(n)+∑_{k=0}^n x(n)\)

=\(y(-1)+ ∑_{k=0}^n n*u(n)\)

=\(0+∑_{k=0}^n n\)(since u(n)=1 in 0 to n)

=\(\frac{n(n+1)}{2}\)

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