# Find Norton equivalent resistance, RN, and equivalent current source, in, at terminals a and b of the circuit.

### Right Answer is:

R_{N} = 4 Ω, i_{N} = 1 A

#### SOLUTION

For Norton resistance, replace the sources with their internal resistance.

The voltage source is replaced by short-circuited and the current source is replaced by open-circuited.

Then finding the equivalent resistance across terminals ab

Resistance 8Ω, 4Ω & 8Ω are connected in series

R = (8 + 4 + 8) = 20Ω

Finally, 20Ω is parallel with 5Ω

R_{eq} = R_{N} = R_{th} = 20||5

R_{eq} = (20 × 5)/(20 + 5)

R_{eq} = 4Ω

For finding the Norton current, a-b terminals are shorted and therefore the 5-ohm resistor is eliminated and converting voltage source into the current source.

Total current = 2A + 3 A = 5A

Applying the current divider rule

I_{N} = (4 × 5)/(4 + 8 + 8)

I_{N} = 1 A