SOLUTION

Concept:

Turns ratio for the transformer is given by

$\frac{{{V_p}}}{{{V_s}}} = \frac{{{I_s}}}{{{I_p}}} = \frac{{{N_p}}}{{{N_s}}}$

Where,

V_p is voltage on primary side

V_s is voltage on secondary side

I_p is current on primary side

I_s is current on secondary side

N_p is turns on primary side

N_s is turns on secondary side

Ratio of input power P_p to output power P_s

$\frac{{{P_p}}}{{{P_s}}} = \frac{{{V_p}{I_p}}}{{{V_s}{I_s}}}$

Calculation:

Given primary-to-secondary turns ratio

$\dfrac{{{N_P}}}{{{N_S}}} = \dfrac{N}{1}$

The instantaneous input power to instantaneous output power is given by

$\begin{array}{l}\dfrac{{{P_i}}}{{{P_o}}} = \dfrac{{{V_i}{I_i}}}{{(N{V_i})\left( {\dfrac{1}{N}{I_i}} \right)}}\\\\\dfrac{{{P_i}}}{{{P_o}}} = 1:1\end{array}$