In the case of full-wave rectifier, the ripple factor is
Right Answer is:
0.48
SOLUTION
Ripple factor: The output of the rectifier is of pulsating D.C type. The amount of a.c. content in the output can be mathematically expressed by a factor called the ripple factor. Less is the ripple factor, better is the performance of the circuit.
The ratio of the R.M.S value of the A.C component to the average value of d.c. component In the output is known as the ripple factor (Γ).
$\Gamma = \sqrt {{{\left( {\frac{{{V_{Rms}}}}{{{V_{DC}}}}} \right)}^2} – 1}$
For Full-wave rectifier, the Average value of the DC component & the RMS value of AC is given as
Average value of dc = (2Vm ⁄ π)
R.M.S Value = Vm ⁄ √2
$\begin{array}{l}\Gamma = \sqrt {{{\left( {\dfrac{{{V_{Rms}}}}{{{V_{DC}}}}} \right)}^2} – 1} \\\\\Gamma = \sqrt {{{\left( {\dfrac{{{V_m}/\sqrt 2 }}{{2{V_m}/\pi }}} \right)}^2} – 1} \\\\\Gamma = \sqrt {{{\left( {\dfrac{\pi }{8}} \right)}^2} – 1} \\\\\Gamma = 0.482\end{array}$