# Image Enhancement in Digital Image Processing MCQ [Free PDF] – Objective Question Answer for Image Enhancement in Digital Image Processing Quiz

71. For a local enhancement using mean and variance, there is one condition: ms(x, y) ≤ k0 MG, where, MG is global mean, k0 a constant, and ms(x, y) a measure of gray value as light or dark at point (x, y). Then, which fact is true for k0?

A. It is a negative constant with values less than -1.0
B. It is a positive constant with values less than 1.0
C. It is an integer constant with values between -1.0 and 1.0
D. None of the mentioned

Answer: B

In the condition ms(x, y) ≤ k0 MG, k0 is a positive constant whose value is always less than 1.0.

72. For a local enhancement using mean and variance, there is one condition: σs(x, y) ≤ k2DG, where, MDG is global standard deviation, k2 a positive constant, and σs(x, y) a measure of contrast at point (x, y). Then, which fact is true for k2 if its value is less than 1.0?

A. Enhancement is being done in light areas
B. Enhancement is being done in dark areas
C. Enhancement is being done independently of the value of k0
D. None of the mentioned

Answer: B

In the condition σs(x, y) ≤ k2DG, k0 is a positive constant that helps in enhancing light areas if the value is greater than 1.0 and dark areas if the value is less than 1.0.

73. For a local enhancement using mean and variance, there is one condition: σs(x, y) ≤ k2DG, where, MDG is global standard deviation, k2 a positive constant, and σs(x, y) a measure of contrast at point (x, y). Then, which fact is true for k2 if its value is greater than 1.0?

A. Enhancement is being done in light areas
B. Enhancement is being done in dark areas
C. Enhancement is being done independently of the value of k0
D. None of the mentioned

Answer: A

In the condition σs(x, y) ≤ k2DG, k0 is a positive constant that helps in enhancing light areas if the value is greater than 1.0 and dark areas if the value is less than 1.0.

74. What is the standard deviation value for the constant area?

A. 0
B. 1
C. -1
D. None of the mentioned

Answer: A

The standard deviation value for the constant area is 0.

75. For a local enhancement using mean and variance, what happens if the lowest value of contrast is not restricted as per the willingness to accept of value?

A. There wouldn’t be any enhancement
B. Enhancement will occur for areas with a standard deviation value > 1
C. Enhancement of the constant areas will also be the part of the procedure
D. Enhancement will occur for areas with standard deviation values> 0 and < 1

Answer: C

If the lowest value of contrast is not restricted as per the willingness to accept of value, the Enhancement of the constant areas will also be part of the procedure, since a constant area has a standard deviation value of e 0.

76. Logic operations between two or more images are performed on a pixel-by-pixel basis, except for one that is performed on a single image. Which one is that?

A. AND
B. OR
C. NOT
D. None of the mentioned

Answer: C

Although all the Arithmetic/Logic operations between two or more images are performed on a pixel-by-pixel basis, except for NOT that is performed on a single image.

77. Which of the following logical operator(s) is/are functionally complete?

A. AND
B. OR
C. NOT
D. All of Mentioned

Answer: D

AND, OR, NOT logical operators given are functionally complete because all other logical operators can be implemented using these three.

78. While implementing logic operation on gray-scale images, the processing of pixel values is done as __________

A. String of integer numbers
B. String of floating numbers
C. String of binary numbers
D. None of the mentioned

Answer: C

Logic operations on gray-scale images are done by the processing of pixel values as strings of binary numbers.

79. What is the equivalent for a black, 8-bit pixel to be processed under logic operation on a grayscale image?

A. A string: 00000000
B. A string: 11111111
C. A string: 10000000
D. A string: 01111111

Answer: A

Logic operations on gray-scale images are done by the processing of pixel values as string of binary numbers, so, a black, 8-bit pixel is processed as a string of eight 0’s.

80. Which of the following operation(s) is/are equivalent to negative transformation?

A. AND
B. OR
C. NOT
D. All of Mentioned

Answer: C

Applying the NOT operator on a black, 8-bit pixel gives a white, 8-bit pixel, so, is equivalent to negative transformation.

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