1. Find the value of I1, I2 and I3 using Kirchoff’s Law.
A. − 0.566A, 1.29A, − 1.91A
B. − 1.29A, − 0.566A, 1.91A
C. 1.29A, − 0.566A, − 1.91A
D. 1.91A, 0.566A, 1.29A
Answer: C
Using the matrix method:
Matrix(3, − 2,0) (I1) = (5)
( − 2,9, − 4) (I2) = (0)
(0, − 4,9) (I3) = ( − 15)
Solving this matrix equation, we get
I1 = 1.29A, I2 = − 0.566A and I3 = − 1.91A.
2. Find the value of V, if the value of I3 = 0A.
A. 1.739 V
B. 6.5 V
C. 4.5V
D.2.739V
Answer: A
5 − 3I1 + 2I2 = 0, 9I2 − 2I1 = 0
− 4I2 + V = 0
On solving,
V = 1.739V.
3. Find the value of R if the power in the circuit is 1000W.
A. 10 ohm
B. 9 ohm
C. 8 ohm
D. 7 ohm
Answer: C
To find the value of I:
VI = P = >100I = 1000 = > I = 10A.
Voltage across the 2 ohm resistor = 20V.
Voltage across the R resistor = 100 − 20 = 80V.
R = V/I = > R = 80/10 = 8A.
4. Find the current in the 4 − ohm resistor.
A. 5A
B. 0A
C. 2.2A
D. 20A
Answer: B
The 4-ohm resistor gets shorted since the current always prefers the low resistance path. All the current flows to the branch which is connected in parallel to the 4-ohm branch, hence no current flows in the 4-ohm resistance.
5. Nodal analysis is generally used to determine______
A. Voltage
B. Current
C. Resistance
D. Power
Answer: A
The nodal analysis uses Kirchhoff’s Current Law to find all the node voltages. Hence it is a method used to determine the voltage.
6. Mesh analysis is generally used to determine _________
A. Voltage
B. Current
C. Resistance
D. Power
Answer: B
Mesh analysis uses Kirchhoff’s Voltage Law to find all the mesh currents. Hence it is a method used to determine current.
7. KVL is associated with____________
A. Mesh analysis
B. Nodal analysis
C. Both mesh and nodal
D. Neither mesh nor nodal
Answer: A
KVL employs mesh analysis to find the different mesh currents by finding the IR products in each mesh.
8. KCL is associated with_________
A. Mesh analysis
B. Nodal analysis
C. Both mesh and nodal
D. Neither mesh nor nodal
Answer: B
KCL employs nodal analysis to find the different node voltages by finding the value of a current in each branch.
9. Calculate the value of V1 and V2.
A. 4V, 6V
B. 5V, 6V
C. 6V, 7V
D. 7V, 8V
Answer: A
Using KVL
12−V1 − 8 = 0.
V1 = 4V.
8 − V2 − 2 = 0
V2 = 6V.
10. KVL deals with the conservation of?
A. Mass
B. Momentum
C. Charge
D. Energy
Answer: D
KVL states that the sum of the potential energy and taken with the right sign is equal to zero, hence it is the conservation of energy since energy doesn’t enter or leave the system.