# Linear Integrated Circuit Power Amplifier MCQ [Free PDF] – Objective Question Answer for Linear Integrated Circuit Power Amplifier Quiz

11. Determine the work done by the intercom system depending on the position of the switch

A. Remote speaker acts  as a microphone
B. Master speaker acts  as a microphone
C. Remote and master speaker act as a microphone
D. None of the mentioned

When the switch of the intercom system is in the listen mode, the remote speaker acts as the microphone.

12. Free running multivibrator is also called as

A. Stable multivibrator
B. Voltage control oscillator
C. Square wave oscillator
D. Pulse stretcher

Free-running multivibrator operates at a frequency that is determined by an external tuning capacitor and a resistor. On applying a dc control voltage the frequency can be shifted on either side. This frequency deviation is directly proportional to the dc control voltage and hence it is called as ‘voltage controlled oscillator’.

13. The output voltage of the phase detector is

A. Phase voltage
B. Free running voltage
C. Error voltage
D. None of the mentioned

The phase detector compares the input frequency with the feedback frequency and produces output dc voltage called error voltage.

14. At which state the phase-locked loop tracks any change in input frequency?

A. Free running state
B. Capture state
C. Phase-locked state
D. All of the mentioned

In the phase-locked, the output frequency is the same as the input signal frequency. So the circuit tracks any change in the input frequency through its repetitive action.

15. Match List I with List II which represents the three stages of a phase-locked loop. (PLL)

 List I List II 1. Before input frequency applied i. PLL-Phase locked state 2. When the input frequency applied ii.PLL=Free running state 3. After input frequency applied iii. PLL-Capture mode

A. 1-ii, 2-iii, 3-i
B. 1-iii, 2-ii, 3-i
C. 1-i, 2-ii, 3-iii
D. 1-ii, 2-i, 3-iii

Before the input is applied, the PLL is free-running. Once the input frequency is applied, the VCO frequency starts to change & PLL is said to be in capture mode. When the VCO frequency continues to change until it is equal to the input frequency, the PLL is said to be in the phase-locked state.

16. What is the function of a low pass filter in a phase-locked loop?

A. Improves low-frequency noise
B. Removes high-frequency noise
C. Tracks the voltage changes
D. Changes the input frequency

The output voltage of a phase detector is a dc voltage and is often referred to as error voltage. This output is applied to the low pass filter which removes the high-frequency noise and produces a dc level.

17. What is the need to generate corrective control voltage?

A. To maintain the lock
B. To track the frequency change
C. To shift the VCO frequency
D. All of the mentioned

The output frequency(fo) of VCO is identical to input frequency(fs) except for a finite phase difference(φ), which generates a corrective control voltage to shift VCO frequency from fo to fs, thereby maintaining the lock once locked and PLL tracks the frequency changes of the input signal.

18. At what range the PLL can maintain the lock in the circuit?

A. Lock in range
B. Input range
C. Feedback loop range
D. None of the mentioned

The change in frequency of the incoming signal can be tracked when the PLL is locked. So, the range of frequencies over which PLL maintains the lock with the incoming signal is called the lock-in range.

19. The pull-in time depends on

A. Initial phase and frequency difference between two sign
B. Overall loop gain
C. Loop filter characteristics
D. All of the mentioned

The pull-in time depends on the above-mentioned characteristics to establish a lock in the PLL circuit.

20. Analog phase detector is often referred as

A. Full-wave detector
B. Half wave detector
C. Rectifier wave detector
D. None of the mentioned

Analog phase detector is called a half-wave detector because the phase information for only one-half of the input waveform is detected and averaged.

21. What happens when VCO output is 90o out of phase with respect to the input signal?

A. Perfect lock
B. Attenuation
C. Shift in the phase of comparator
D. Error signal is removed

The error voltage is zero when the phase shift between the two inputs is 90o. So, for the perfect lock, the VCO output should be 90o out of phase with respect to the input signal.

22. Find the error voltage of the phase comparator whose input signal is Vs= Vssin(2πfst) and the output signal Vo= Vosin(2πfot+φ).

A. Ve=[k×(Vs/2)]×[cos(-φ)-cos(2πfot+φ)].
B. Ve=[k×Vs×(Vo/2)]×[cos(-φ)-cos(2πfot+φ)].
C. Ve=[k×Vs×(Vo/2)]×[cos(-φ)+cos(2πfot+φ)].
D. Ve=[k×Vs×Vo]×[cos(-φ)-cos(2πfot+φ)].

A phase comparator is basically a multiplier which multiplies the input signal by the VCO signal.

Thus, the phase comparator output

= Vs×Vo = Vs×Vosin(2πfst)× sin(2πfot+φ)

=k×Vs×Vo ×sin(2πfst)×sin(2πfot+φ)

Where

k – phase comparator gain.

= k×Vs×Vo/2[cos(-φ)-cos(2πfot+φ)]

When at lock, fs =fo

=> Ve = Ve={k×Vs× Vo/2}x[cos(-φ)-cos(2πfot+φ)].

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