Magnetic Field of Solenoid MCQ [Free PDF] – Objective Question Answer for Magnetic Field of Solenoid Quiz

22. When the length of the conductor in the current-carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Answer: A

The force at right angles to the magnetic field of a current-carrying conductor increases when the length of the conductor increases because it is directly proportional to the force.

 

23. When the magnetic field intensity in the current-carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?

A. Increases
B. Decreases
C. Remains the same
D. Becomes zero

Answer: A

The force at right angles to the magnetic field of a current-carrying conductor increases when the magnetic field intensity increases because it is directly proportional to the force.

 

24. The unit for force in a current-carrying conductor is _________

A. Tesla × Ampere × meter
B. Tesla
C. Ampere/meter
D. Ampere × meter

Answer: A

The Magnetic Force on a Current is expressed as

F = B × i × l.

So, a unit of force = unit of B × unit of I × unit of l = Tesla × Ampere × meter.

 

25. If the net force is zero on a particle in a magnetic field what is the relation between velocity and magnetic field?

A. v = E × B
B. v = E/B
C. v = B/E
D. v = 1/(E × B.

Answer: B

Since net force is zero on the particle.

Electric force = Magnetic force

QE = QvB = > E = vB or v = E/B.

 

26. If the intensity of the magnetic field is 100T, the length of the conductor is 10m and the magnitude of force perpendicular to the magnetic field is 10kN, calculate the current in the conductor.

A. 100 A
B. 100 mA
C. 10 A
D. 10 mA

Answer: C

The formula for calculating the value of the force which is perpendicular to the magnetic field is:

F = Bil

Substituting the values from the question, we get i = 10A.

 

27. If the intensity of the magnetic field perpendicular to the current-carrying conductor is 100T, the length of the conductor is 3m and the current in the conductor is 10A, calculate the magnitude of force perpendicular to the electric field.

A. 300N
B. 30N
C. 30kN
D. 3kN

Answer: D

The formula for calculating the value of the force which is perpendicular to the magnetic field is:

F = Bil

Substituting the values from the question,

we get F = 3kN.

 

28. Force in a current-carrying conductor placed in a magnetic field is ___________ of il and B.

A. dot product
B. scalar product
C. cross product
D. vector addition

Answer: C

Force in a current-carrying conductor is given by the cross product of il and B.

F = BIL

Where

F is force in newtons (N)

B is magnetic flux density (magnetic field strength) in tesla (T)

I is current in amperes – also referred to as amps (A)

 

29. An E.M.F. can be induced by _________

A. Change in the magnetic field only
B. Change in the area of cross-section only
C. Change in angle between magnetic field and area only
D. Change in the magnetic field, area, or angle between them

Answer: D

emf = -dϕ/dt.

We know ϕ flux is the dot product of the magnetic field vector and area vector.

ϕ = BAcos(θ),

hence if either of the three, that is, magnetic field, area, or angle changes, the emf will change, and flux changes due to which emf can be induced.

 

30. What happens to the current in a coil while accelerating a magnet inside it?

A. Increases
B. Decreases
C. Remains constant
D. Reverses

Answer: A

A change in the magnetic field induces an emf. When there is an emf, there has to be current. Hence, when the magnet is moved inside a coil, the current in it increases.

 

31. What is the consequence of the motor effect?

A. Current
B. Voltage
C. Electromagnetic induction
D. EMF

Answer: C

The motor effect is when a current-carrying conductor in a magnetic field experiences a force, hence its consequence is electromagnetic induction.

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