Mesh Analysis MCQ [Free PDF] – Objective Question Answer for Mesh Analysis Quiz

11. Mesh analysis is applicable for non-planar networks also.

A. true
B. false

Answer: B

Mesh analysis is applicable only for planar networks. A circuit is said to be planar if it can be drawn on a plane surface without crossovers.

 

12. A mesh is a loop that contains ____ number of loops within it.

A. 1
B. 2
C. 3
D. no loop

Answer: D

A loop is a closed path. A mesh is defined as a loop that does not contain any other loops within it.

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13. Consider the circuit shown below. The number mesh equations that can be formed are?

Consider the circuit shown below. The number mesh equations that can be formed are?

A. 1
B. 2
C. 3
D. 4

Answer: B

We know if there are n loops in the circuit, n mesh equations can be formed. So as there are 2 loops in the circuit. So 2 mesh equations can be formed.

 

14. In the figure shown below, the current through loop 1 be I1 and through loop 2 be I2, then the current flowing through the resistor R2 will be?

Consider the circuit shown below. The number mesh equations that can be formed are?

A. I1
B. I2
C. I1 − I2
D. I1 + I2

Answer: C

Through the resistor R2 both the currents, I1 and I2 are flowing. So the current through R2 will be I1 − I2.

 

15. If there are 5 branches and 4 nodes in the graph, then the number of mesh equations that can be formed is?

A. 2
B. 4
C. 6
D. 8

Answer: A

Number of mesh equations

= B − (N − 1).

Given a number of branches = 5 and number of nodes = 4.

So Number of mesh equations = 5 − (4 − 1) = 2.

 

16. Consider the circuit shown in the figure. Find voltage Vx.

Consider the circuit shown in the figure. Find voltage Vx.

A. 1
B. 1.25
C. 1.5
D. 1.75

Answer: B

Consider current I1 (CW) in loop 1 and I2 (ACW) in loop 2.

So, the equations will be

Vx + I2 − I1 = 0.

I1 = 5/2 = 2.5A

I2 = 4Vx/4

= Vx. Vx + Vx − 2.5 = 0.

Vx  = 1.25V.

 

17. Consider the circuit shown below. Find the current I1.

Consider the circuit shown below. Find the current I1.

A. 3.3
B. 4.3
C. 5.3
D. 6.3

Answer: B

According to mesh analysis,

(1 + 3 + 6)I1 – 3(I2) – 6(I3) = 10

− 3(I1) + (2 + 5 + 3)I2

= 4 − 6(I1) + 10(I3) = − 4 + 20

On solving the above equations, I1 = 4.3A.

 

18. Consider the following figure. Find the current I2 (A)

Consider the circuit shown below. Find the current I1.

A. 1.7
B. 2.6
C. 3.6
D. 4.6

Answer: A

According to mesh analysis

(1 + 3 + 6)I1 – 3(I2) – 6(I3) = 10.

− 3(I1) + (2 + 5 + 3)I2  = 4.

− 6(I11) + 10(I3) = − 4 + 20

On solving the above equations,

I2  = 1.7A.

 

19. Consider the following figure. Find the current I3 (A)

Consider the circuit shown below. Find the current I1.

A. 4
B. 4.7
C. 5
D. 5.7

Answer: B

According to mesh analysis

(1 + 3 + 6)I1 – 3(I2) – 6(I3) = 10

− 3(I1) + (2 + 5 + 3)I2  = 4.

− 6(I1) + 10(I3) = − 4 + 20.

On solving the above equations, I3  = 4.7A.

 

20. Find the current through the R2 resistor.

Find the current through R2 resistor.

A. 3
B. 3.25
C. 3.5
D. 3.75

Answer: D

Applying mesh analysis

5(I1) + 2(I1 − I2) = 10

10(I2) + 2(I2 − I1) + 40 = 0.

On solving

I1  = 0.5A, I2  = − 3.25A.

So current through R2 resistor is 0.5 − ( − 3.25) = 3.75 A

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