11. Which circuit allows doubling the frequency?
A. Frequency doubler
B. Square doubler
C. Double multiplier
D. All of the mentioned
12. Compute the output of the frequency doubler. If the inputs Vx = Vsinωt and Vy = Vision(ωt+θ) are applied to a four-quadrant multiplier?
A. Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/ Vref
B. Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/ 2
C. Vo= { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/(2×Vref)
D. Vo= – { Vx×Vy× [cosθ-(cosθ×cos2ωt)+(sinθ×sin2ωt)]}/(2×Vref)
13. How to remove the dc term produced along with the output in the frequency doubler?
A. Use a capacitor between load and output terminal
B. Use a resistor between load and output terminal
C. Use an Inductor between load and output terminal
D. Use a potentiometer between load and output terminal
14. Find the voltage range at which the multiplier can be used as a squarer circuit?
A. 0 – Vin
B. Vref – Vin
C. 0 – Vref
D. All of the mentioned
15. Calculate the output voltage of a squarer circuit, if its input voltage is 3.5v. Assume Vref = 9.67v.
A. 2.86v
B. 1.27v
C. 10v
D. 4.3v
16. Which circuit can be used to take the square root of a signal?
A. Divider circuit
B. Multiplier circuit
C. Squarer circuit
D. None of the mentioned
17. Find the output voltage of squarer circuit?
A. Vo = √( Vref/|Vin|)
B. Vo = √( Vref×|Vin|)
C. Vo = √( Vref2×|Vin|)
D. Vo = √( Vref×|Vin|2)
18. Find the current, IL flowing in the circuit given below
A. IL = 1.777mA
B. IL = 1.048mA
C. IL = 1.871mA
D. None of the mentioned
19. A square root circuit built from the multiplier is given an input voltage of 11.5v. Find its corresponding output voltage?
A. 11v
B. 15v
C. 13v
D. Cannot be determined
20. The circuit in which the output voltage waveform is the integral of the input voltage waveform is called
A. Integrator
B. Differentiator
C. Phase shift oscillator
D. Square wave generator
21. Find the output voltage of the integrator
A. Vo = (1/R×CF)×t∫0 Vindt+C
B. Vo = (R/CF)×t∫0 Vindt+C
C. Vo = (CF/R)×t∫0 Vindt+C
D. Vo = (R×CF)×t∫0 Vindt+C
22. Why an integrator cannot be made using a low pass RC circuit?
A. It requires a large value of R and a small value of C
B. It requires a large value of C and a small value of R
C. It requires a large value of R and C
D. It requires a small value of R and C
23. How a perfect integration is achieved in op-amp?
A. Infinite gain
B. Low input impedance
C. Low output impedance
D. High CMRR