SOLUTION

Circuit diagram:

Two terminals of Op-Amp i.e.; Inverting Terminal and Non-Inverting Terminal are at equipotential.

Apply KCL at node 1 V_pp,

$\begin{array}{l} \dfrac{{1{V_{pp}} – 0}}{{10\:k}} + \dfrac{{1{V_{pp}} – {V_0}}}{{100k}} = 0\\ \\ \dfrac{{10{V_{pp}} + 1{V_{pp}} – {V_0}}}{{100K}} = 0 \end{array}$

11V_pp − V_O = 0

Closed-loop gain is given by the ratio of output to the input.

so the Closed-loop voltage gain is given by,

V_O/V_PP = 11