The open-loop gain-bandwidth product of an op-amp is given as 10,000 Hz
The open-loop gain-bandwidth product of an op-amp is given as 10,000 Hz. The op-amp is used in an inverting amplifier as shown in the figure. The bandwidth of the inverting amplifier is
Right Answer is:
2000 Hz
SOLUTION
Given
Gain × bandwidth = 10,000 Hz
Applying nodal analysis at Vin and V−
(Vin − 0)/20 = (0 − Vo)/100
Vin /20 = − Vo/100
Gain = |Vo/Vin| = 5
∵ Gain × bandwidth = 10,000 Hz
= 5 × bandwidth = 10,000 Hz
Bandwidth = 10000/5
Bandwidth = 2000 Hz