31. A step-index fiber has a core refractive index of 1.46 and a radius of 4.5μm. Find the cutoff wavelength to exhibit single-mode operation. Use relative index difference as 0.25%.
a) 1.326μm
b) 0.124μm
c) 1.214μm
d) 0.123μm
Answer: 3. 1.214μm
Explanation:
A step-index fiber is fiber type cylindrical waveguide core with an inner core has a uniform refractive index of n1 and the core is surrounded by an outer cladding with a uniform refractive index of n2.
32. A step-index fiber has a core refractive index of 1.46 and a radius of 4.5μm. Find the Numerical Aperature to exhibit single-mode operation. Use relative index difference as 0.25%.
0.707
1.085
2.4
707
Answer: 3. Hondros and debye
Explanation:
Given
core radius,= 4.5 μm
Refractive index difference Δ0.25% = 0.0025
Core refractive index n1 = 1.46
Numerical Aperature = n1(2Δ)1/2
= 1.46(2× 0.0025)1/2
NA = 0.707
33. A single-mode step-index fiber allows propagation of only one transverse ________
Magnetic wave
Electrical Wave
Electromagnetic wave
None of the above
Answer: 3. Electromagnetic wave
Explanation:
Single-mode step-index fiber allows the propagation of only one transverse electromagnetic mode.
The core diameter is of the order of 2 to 10 µm.
As single-mode fibers support only one mode, these types of fibers do not exhibit Intermodal dispersion, whereas with multimode step-index fibers considerable dispersion may take place due to different group velocities of the propagating modes.
34. The core diameter of the single-mode step-index fiber is
10 to 20 µm
2 to 10 µm
20 to 40 µm
50 to 100 µm
Answer: 2. 2 to 10 µm
Explanation:
Single-mode step-index fiber allows the propagation of only one transverse electromagnetic mode.
The core diameter is of the order of 2 to 10 µm.
As single-mode fibers support only one mode, these types of fibers do not exhibit Intermodal dispersion, whereas with multimode step-index fibers considerable dispersion may take place due to different group velocities of the propagating modes.
35. One of the given statements is true for intermodal dispersion. Choose the right one.
a) Low in single-mode and considerable in multimode fiber
b) Low in both single-mode and multimode fiber
c) High in both single-mode and multimode fiber
d) High in single-mode and low in multimode fiber
Answer: 1. Low in single-mode and considerable in multimode fiber
Explanation:
Single-mode step-index fiber allows the propagation of only one transverse electromagnetic mode.
The core diameter is of the order of 2 to 10 µm.
As single-mode fibers support only one mode, these types of fibers do not exhibit Intermodal dispersion, whereas with multimode step-index fibers considerable dispersion may take place due to different group velocities of the propagating modes.
36. For lower bandwidth applications _______
a) Single-mode fiber is advantageous
b) Photonic crystal fibers are advantageous
c) Coaxial cables are advantageous
d) Multimode fiber is advantageous
Answer: 1. Multimode fiber is advantageous
Explanation:
The single-mode step-index fiber has the distinct advantage of low intermodal dispersion (broadening of transmitted light pulses), as only one mode is transmitted
With multimode step-index fiber, a considerable dispersion may occur due to the different group velocities of the propagating modes. This, in turn, restricts the maximum bandwidth attainable with multimode step-index fibers, especially when compared with single-mode fibers.
In multimode fibers, intermodal dispersion occurs. The group velocities often differ which gradually restricts maximum bandwidth attainability in multimode fibers.
However, for lower bandwidth applications, multimode fibers have several advantages over single-mode fibers.
The use of spatially incoherent optical sources (e.g., most light-emitting diodes) cannot be efficiently coupled to single-mode fibers.
Larger numerical apertures, as well as core diameters, facilitate easier coupling to optical sources.
Lower tolerance requirements on fiber connectors.
37. Most of the optical power is carried out in ______ region than in ______.
Core, Cladding
Cladding, Core
Core, Cable jacket
None of the above
Answer: 1. Core, Cladding
Explanation:
Most of the optical power is carried out in core region than in cladding.
Cladding in optical fibers is one or more layers of materials of lower refractive index, in intimate contact with a core material of higher refractive index. The cladding causes light to be confined to the core of the fiber by total internal reflection at the boundary between the two.
The core of a conventional optical fiber is the part of the fiber that guides the light. It is a cylinder of glass or plastic that runs along the fiber’s length. The core is surrounded by a medium with a lower index of refraction, typically a cladding of different glass, or plastic.
In an ideal multimode fiber, there is no mode of coupling. The optical power launched into a particular mode remains in that mode itself. The majority of these modes are mostly confined to fiber core only.
38. Meridional rays in graded-index fibers follow ______
a) Straight path along the axis
b) Curved path along the axis
c) Path where rays changes angles at core-cladding interface
d) Helical path
Answer: 3. Curved path along the axis
Explanation:
Meridional rays pass through the axis of the fiber core. Meridional rays shown appear to follow curved paths through the fiber core. This may be described using the concepts of geometrical optics. The gradual decrease in refractive index from the center of the core creates a large number of refractions of the rays as they are effectively incident on many high to low index interfaces.
This ray indicates the transmission of light in a perfect optical fiber.
Meridional rays can be of two types :
(i) Bound rays
(ii) Unbound rays.
The bound rays follow total internal reflection in the fiber core and do not escape out of the fiber core.
Unbound rays are refracted out of the fiber core and are absorbed in the cladding.
39. What is the unit of normalized frequency?
a) Hertz
b) Meter/sec
c) Coulombs
d) It is a dimensionless quantity
Answer: 4. It is a dimensionless quantity
Explanation:
The normalized frequency of optical fiber is the frequency that exists at the cut-off condition. There is no propagation and attenuation above the cut-off. It is directly proportional to the numerical aperture which is a dimensionless quantity; hence itself is a dimensionless quantity.
Normalized frequency for a graded-index fiber is given by