In a 3 phase power measurement by two wattmeter method, the reading of one-wattmeter is zero. The power factor of the load is

In a 3 phase power measurement by two wattmeter method, the reading of one-wattmeter is zero. The power factor of the load is

Right Answer is:

0.5

SOLUTION

As given in the above question

W1 = 1700 W

W2 = 1100 W

The power factor of the two wattmeters is

tanØ =  √3[(W1 – 0) / (W1 +0)]

tanØ = √3

Φ = 60°

Power factor = cosφ = cos60° = 0.5

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