In a 3 phase power measurement by two wattmeter method, the reading of one-wattmeter is zero. The power factor of the load is
In a 3 phase power measurement by two wattmeter method, the reading of one-wattmeter is zero. The power factor of the load is
Right Answer is:
0.5
SOLUTION
As given in the above question
W1 = 1700 W
W2 = 1100 W
The power factor of the two wattmeters is
tanØ = √3[(W1 – 0) / (W1 +0)]
tanØ = √3
Φ = 60°
Power factor = cosφ = cos60° = 0.5