Ques.120. In a parallel RLC circuit if the lower cut-off frequency is 2400 Hz and the uppercut off frequency is 2800 Hz, What is the bandwidth? (SSC-2015)
2800 Hz
2400 Hz
400 Hz
5200 Hz
Answer.3. 400 Hz
Explanation:-
Bandwidth = upper frequency – lower frequency
Bandwidth = f1 – f2
2800 – 2400
400 Hz.
Ques.121. Two wires A and B have the same cross-section and are made of the same material. RA = 800Ω and RB = 100Ω. The number of times A is longer than B is (SSC-2014, M-Shift)
5
6
2
4
None of the options is correct
Explanation:-
Since they are of the same material they will have the same resistivity.
Therefore their length now
Ra/Rb=la/lb
800/100 = la/lb
la = 8lb
Therefore A is 8 times longer than B
Ques.122. In the circuit shown in the figure, find the transient current i(t) when the switch is closed at t = 0, Assume zero initial condition.
50 t e-0.5t
50 t e-5t
100 t e-5t
100 t e-0.5t
Answer.3. 100 t e-5t
Explanation:-
Ques.123. The power factor of the circuit shown in figure: (SSC-2014, M-Shift)
0.75 lagging
0.6 lagging
0.3 lagging
0.8 lagging
Answer.4. 0.8 lagging
Explanation:-
The power factor of series RL circuit
Due to the inductive circuit power factor is lagging.
Ques.124. The power factor of the A.C circuit is given by: (SSC-2014, M-Shift)
R/Z
XL/R
Z/R
R/XL
Answer.1. R/Z
Explanation:-
In electrical engineering, the power factor of an AC electrical power system is defined as the ratio of the real power flowing to the load to the apparent power in the circuit ” R/Z”.
Ques.125. Two 100 W, 200 V lamps are connected in series across a 200 V supply. The total power consumed by each lamp will be watts: (SSC-2014, M-Shift)
200
25
50
100
Answer.2. 25
Explanation:-
Let’s take a 200 volts – 100 watts bulb and calculate the resistance of its filament :
We know,
P=V2R
or
R=V2P
When V=200 volts and P = 100 watts,
R = (200*200)/100 = 400 ohms.
Since now the two bulbs are in series, the total resistance offered by them is :
R’ = 400 Ω + 400 Ω = 800 Ω
Let them be powered by a 200 volts DC source.
Now the current that flows through either of them is :
I=V/R
=200/800=0.25A
Now total power consumed by each lamp
P=I2 x R
P=(0.25 x 0.25)400
P = 25 watts
Ques.126. The Bio-Savart’s law is a general modification of: (SSC-2014, M-Shift)
Faraday’s law
Kirchhoff’s law
Lenze law
Ampere’s law
Answer.4. Ampere’s law
Explanation:-
Biot-Savart’s law describes the three different types of currents, which is nothing but the filament or line current, surface current and volume current. Hence, this law is a general modification of Ampere’s circuital law.
Ques.127. The active and reactive power of an inductive circuit are 60 W and 80 VAR respectively. The power factor of the circuit is (SSC-2014, M-Shift)
0.8 lag
0.5 lag
0.6 lag
0.75 lag
Answer.3. 0.6 lag
Explanation:-
Active Power P = 60 W
Reactive Power Q = 80 VAR
S =√P2 + Q2 = √602 + 802
= 100 VA
Power factor = cos Φ = P/S = 60/100 =0.6
Second Method
Ques.128. Which of the following is the non-linear circuit parameter? (SSC-2014, M-Shift)
Transistor
Inductance
Condenser
Wire Wound Resistor
Answer.1. Transistor
Explanation:-
A linear circuit is an electric circuit in which circuit parameters (Resistance, inductance, capacitance, waveform, frequency, etc) are constant. In other words, a circuit whose parameters are not changed with respect to Current and Voltage is called Linear Circuit.
Whereas in a non-linear circuit the parameters (Resistance, inductance, capacitance, etc) is not constant, which is called Non-Linear Circuit.
Example : – Diode,transistor,SCR , transformer, iron core, inductor etc.
Ques.129. A terminal where three or more branches meet is known as (SSC-2014, M-Shift)
Mesh
Node
Terminus
Loop
Answer.2. Node
Explanation:-
Junction point
A point where three or more branches meet is called a junction point.
Node
A point at which two or more elements are joined together is called a node. The junction points are also the nodes of the network.
