SSC JE Electrical Previous Year Question Paper 2018-SET1|SSC JE 2018

Ques.41. On which of the following parameters the eddy current loss occurring in material does not depend?

  1. Magnetic flux Density
  2. The frequency of variation of flux
  3. Susceptibility
  4. The volume of the material

Eddy current loss: In the transformer, we provide alternating current in the primary which produces alternating flux in the core, this flux links with the secondary of the transformer and induces emf in the secondary.

It may be possible that flux also links with some other conducting parts of transformer such as ferromagnetic core or iron body and induces local emf in these parts of transformer which will cause a circulating current to flow in these parts causing heat loss. these currents are called eddy currents and this loss is called eddy current loss.

Eddy current losses in the transformer are given by

Eddy current losses = Ke × Bm2 × f2 × V ×t2

Where
Ke = Eddy current constant 
t = thickness of the core
V = Volume of material 
Bm = Maximum flux density
f = frequency 

Hence from the above expression, it is clear that the eddy current losses do not depend on the susceptibility of the material.

 

Ques.42. A house has 5 fans of 70 W each that operate for 16 hours a day and one washing machine of 2000 W that operates for 1 hour per day in the month of June. What is the energy consumption(in kWh) of the house in the month of June?

  1. 228
  2. 235.6
  3. 350
  4. 486.6

Energy consumption or power consumption refers to the electrical energy per unit of time is given as

E = Power × Time = P × T

(i) 5 fans of 70 watts working 16 hours per day

Energy consumption = power × Time = 5 × 70 × 16 = 5600 watt-hr

(ii) One washing machine of 2000 watt operating for 1 hours

Energy consumption = 2000 × 1 = 2000 watt-hr

Energy consumption in the month of June i.e for 30 days

(Energy consumption of Fan + Energy consumption of Washing Machine) × 30

 (5600 + 2000) × 30 = 228000 watt-hr or 228 KWH

 

Ques.43. A PMMC type voltmeter, having a full-scale reading of 250 V and internal resistance of 400 kilo-ohms, is connected with the series resistance of 100 kilo-ohms. Calculate the sensitivity of the voltmeter (in Ohms/Volts).

  1. 2400
  2. 2000
  3. 20000
  4. 24000

Voltmeter sensitivity (ohm per volt ratings)

The sensitivity of a voltmeter is given in ohms per volt. It is determined by dividing the sum of the resistance of the meter (Rm) plus the series resistance (Rs), by the full-scale reading in volts. In equation form, sensitivity is expressed as follows:

Sensitivity (S) = (Rm + Rs) ⁄ Vfld

Now as per the given question

Ans.43

 

Rm = 400 KΩ

Rs = 100 KΩ

Vfld = 250 V

S = (400 + 100) ⁄ 250

S = (500 × 103) ⁄ 250

S = 2000 ohm/volt

 

Ques.44. Determine the percentage voltage error of a potential transformer with the system voltage of 11000 V and having a turn ratio of 104 if the measured secondary voltage is 98 V.

  1. 7.92
  2. 5.75
  3. 6.25
  4. 8.84

System voltage i.e Nominal voltage = 11000 V

V1/V2 = N1/N2

98/V2 = 104

Primary = Turn ratio × Secondary voltage = 98 × 104 = 10192 V

Percentage of error is the Potential error

= (Nominal voltage − Primary voltage)/Primary voltage

(11000 − 10192)/10192

= 7.92%

 

Ques.45. A circuit having a power factor of 0.8 consumes 40 W. What will be the value of reactive power (in VAR) of the circuit?

  1. 20
  2. 40
  3. 30
  4. 10

The power triangle or Impedance triangle of the AC circuit is shown Below

Reactive power 2

Cosφ = Base ⁄ Hypotenuse = Active Power  ⁄ Apparent Power

Active Power = Apparent power × Cosφ

Sinφ = Perpendicular ⁄ Hypotenuse = Reactive Power  ⁄ Apparent Power

Reactive Power = Apparent power × Sinφ

or

Reactive Power = (Active Power × Sinφ) ⁄ Cosφ

cosφ = 0.8

Sin2φ = 1 − cos2φ

Sin2φ = 1 − (0.8)2

Sinφ = 0.6

Reactive Power =(40 × 0.6) ⁄ 0.8

Reactive Power = 30 VAR

 

Ques.46. Determine the phase angle (in degrees) of a balanced 3-phase star connected system, if the first and the second wattmeter show reading of 200 W and 1200 W respectively.

  1. 51
  2. 65
  3. 78
  4. 84

Reading of Wattmeter 1 W1 = 200 W

Reading of Wattmeter 2 W2 = 1200 W

The power factor of the two wattmeters is given as

$\begin{array}{l}\tan \Phi = \sqrt 3 \left( {\left| {\dfrac{{{W_1} – {W_2}}}{{{W_1} + {W_2}}}} \right|} \right)\\\\\tan \Phi = \sqrt 3 \left( {\left| {\dfrac{{200 – 1200}}{{200 + 1200}}} \right|} \right)\\\\\tan \Phi = \sqrt 3 \left| {\dfrac{{ – 1000}}{{1400}}} \right|\\\\\tan \Phi = \dfrac{{\sqrt 3 }}{{1.4}}\\\\\tan \Phi = 1.237\\\\\Phi = {\tan ^{ – 1}}1.237\\\\\Phi = {51^ \circ }\end{array}$

 

Ques.47. Which one of the following statements is NOT true about PMMC type instruments?

  1. PMMC type Instruments have uniformly divided scale
  2. These instruments are suitable for both AC and DC currents
  3. Stray magnetic errors are small in these types of instruments
  4. The cost of PMMC instruments is high

The principle on which a Permanent Magnet Moving Coil (PMMC) instrument operates is that torque is exerted on a current-carrying coil placed in the field of a permanent magnet.

PMMC type of instrument can be operated in direct current only. In alternating current, the instrument does not operate because in the positive half the pointer experiences a force in one direction, and in the negative half, the pointer experiences the force in the opposite direction. Due to the inertia of the pointer, it remains in its zero position.

 

Ques.48. Which of the following instrument can measure voltage resistance and current?

  1. Ammeter
  2. Voltmeter
  3. Multimeter
  4. Wattmeter
A multimeter is a very useful electronic instrument that can be used for the measurement of three quantities, namely voltage, current, and resistance. This instrument can also be used for both dc and ac voltages and currents. Multimeters are available in both analog and digital forms. Although analog multimeters are being replaced by digital multimeters.

Multimeter1

 

Ques.49. Determine the magnetic field strength (in A/m) of a material when the intensity of magnetization of the material is 0.084 Amp/m and the magnetic susceptibility of the material is 0.0012.

  1. 70
  2. 700
  3. 0.7
  4. 0.07

The magnetic susceptibility expresses the responsiveness of a material to the applied magnetic field and can vary with the external applied magnetic field.

The symbol for magnetic susceptibility is χ and the formula is

χ = M/H

Where M = Magnetization = 0.084 Amp/M

H = Magnetic field intensity = ?

∴ Magnetic field Intensity H is

H = M/χ

H = 0.084 ⁄ 0.0012

H = 70 A/m

 

Ques.50. Determine the flux (in Wb) through a coil when the reluctance of the coil is 4 Amp-turns/Wb and the produced MMF is 48 Amp-turns.

  1. 10
  2. 12
  3. 14
  4. 16

The amount of flux produced by the magnet indicates the strength of the magnet. The more the magnetizing force (MMF), the more the flux produced. The more the opposition to the flux path (i.e., reluctance or magnetic resistance) less is the flux produced. This relationship is expressed as

Flux = M.M.F ⁄ Reluctance

Given

M.M.F = 48 Amp-turns

Reluctance = 4 Amp-turns/Weber

Flux = 48 ⁄ 4 = 12 Weber

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