SSC JE 2013 electrical question paper with solution

Ques 70. The high-voltage and low-voltage winding resistances of a distribution transformer of 100 kVA, 1100/220 volts, and 50 Hz are 0.1 Ω and 0.004 Ω respectively. The equivalent resistances referred to high-voltage side and low-voltage side are respectively

  1. 2.504 Ω and 0.2 Ω
  2. 0.2 Ω and 0.08 Ω
  3. 0.10016 Ω and 2.504 Ω
  4. 0.008 Ω and 0.10016 Ω

Answer.2. 0.2 Ω and 0.08 Ω

Explanation:

The high voltage and low voltage winding resistances of a distribution transformer of 100

 

Ques 71. A tank circuit consists of

  1. An inductor and a capacitor are connected in series
  2. An inductor and a capacitor are connected in parallel
  3. A  pure inductance and a pure capacitance are connected in series
  4. A  pure inductance and a pure capacitance are connected in parallel

Answer.4. A pure inductance and a pure capacitance connected in parallel

Explanation:

An LC circuit, also called a resonant circuit, tank circuit, or tuned circuit is an electric circuit consisting of an inductor, represented by the letter L, and a capacitor, represented by the letter C, connected together in Parallel.

 

Ques 73.  The instantaneous power of a 1-phase series circuit supplying R-L load from a sinusoidal voltage source has in each cycle

  1. Negative twice, zero four times
  2. Zero twice, negative once
  3. Negative four times, zero twice
  4. Negative twice, zero once

Answer.1. Negative twice, zero four times

Explanation:

  • Instantaneous power is the power of the object at any instant of time, in general, it is defined as p(t) = v(t) x  i(t)
  • In a single-phase ac circuit, the instantaneous power to a load is of pulsating nature. Even at the unity power factor, the instantaneous power is always less than the unity
  • For a sinusoidal signal,  the voltage swings through zero volts twice a cycle, so the instantaneous power is zero two times per cycle.
  • If the load has both resistance and reactance, then the current, and voltage swings through zero twice a cycle, with different phase angle, and thus the instantaneous power will swing through zero 4 times a cycle.
  • Instantaneous power is positive for one part of the cycle and negative for another part of the cycle if there is both resistance and reactance in the circuit. then there will be one negative for voltage and one negative for current thus instantaneous power will have two negative per cycle for a single-phase R-L series circuit.

 

Ques 74. In a series R-L-C circuit, the “Q-factor” is given by

  1. 1/R√L/C
  2. R√L/C
  3. 1/R√C/L
  4. R√C/L

Answer.1. 1/R√L/C

Explanation:

  • The Q factor is a parameter that describes the resonance behavior of an underdamped harmonic oscillator (resonator).
  • In an ideal series RLC circuit, and in a tuned radio frequency receiver (TRF) the Q factor is: 1/R√L/C
  • The larger the series resistance, the lower the Q factor.

 

Ques 75.  In an ac circuit, V = (200 + j40) V and I = (30 – j 10) A. The active and reactive power of the circuit are respectively

  1. 6400 W, 800 VAR capacitive
  2. 6400 W, 800 VAR inductive
  3. 5600 W, 3200 VAR capacitive
  4. 6400 W, 3200 VAR inductive

Answer.2. 6400 W, 800 VAR capacitive

Explanation:

Active power = 200 x 30 + 40 x10 =6400 W

Reactive Power = 200 x 10 – 40 x 30 = 800 VAR 

 

Ques 76. Application of Norton’s theorem in a circuit results in

  1. A current source and impedance in parallel
  2. A voltage source and impedance in series
  3. An ideal voltage source
  4. An ideal current source

Answer.1. A current source and an impedance in parallel

Explanation:

Norton’s theorem illustrates that a network consists of  several voltage sources, current sources, and resistors with two terminals, which is electrically equivalent to an ideal current source ” INO” and a single parallel  resistor, RNO

 

Ques 77. The voltage (v) vs. current (i) curve of the circuit is shown below:

numerical

numerical 2

  1.  24 Ω
  2. 4 Ω
  3. 10 Ω
  4. 14 Ω

Answer 4. 14 Ω

From the circuit diagram 

e = V – 10i

r = e/i 

= V/i -10

On differentiating

dr = dv/di -10

= 12/0.5 – 10 = 14 Ω

 

Ques 78. The value of the load impedance ZL for which the load consumes maximum power is

load impedance problem

  1. 50 Ω at a power factor of 0.6 lead
  2. 50 Ω at a power factor of 0.6 lag
  3. 30 Ω at a power factor of unity
  4. None of the above

Answer.1. 50 Ω at a power factor of 0.6 lead

Explanation:

For maximum power transfer

ZL = Zs* = 30 – j40

Apparent power

Zs2 = 302 + 402

Zs = 50 Ω

Power factor = Real power/ Apparent power

CosΦ = 30/50 = 0.6 leading

 A leading power factor signifies that the load is capacitive, as the load “supplies” reactive power, and therefore the reactive component  Q is negative as reactive power is being supplied to the circuit.

 

Ques 79. The speed-torque characteristic of a dc series motor operating from a constant voltage supply is

  1. speed torque characterstic 1
  2. speed torque characterstic 2
  3. speed torque characterstic 3
  4. speed torque characterstic 4

Answer.3. speed torque characterstic 3

Explanation:

Speed torque characteristic is also called a mechanical characteristic. From the characteristics of the DC series motor, it can be found that when speed is high, torque is low, and vice versa.

Ques 80. Match List I (Machine) with List-II (graph) and select the appropriate response.

graph matching

  1. a-(iv), b-(iii), c-(i), d-(ii)
  2. a-(iii), b-(iv), c-(ii), d-(i)
  3.  a-(iv), b-(iii), c-(ii), d-(i)
  4. a-(iii), b-(iv), c-(i), d-(ii)

Answer.3. a-(iv), b-(iii), c-(ii), d-(i)

Explanation:

  1. The speed-torque characteristics is graph of DC motor.
  2. Open circuit characteristic is also known as the magnetic characteristic or no-load saturation characteristic. it’s a graph plotted between emf induced and excitation is given ( field current ) at no load. This gives us an idea of how the dc machine is going to behave in certain field current.O.C.C of DC generator
  3. In power engineering & electrical engineering, the V curve is the graph showing the relation of armature current as a function of field current in synchronous machines. The purpose of the curve is to show the variation in the magnitude of the armature current as the excitation voltage of the machine is varied.v curve
  4. The circle diagram is the graphical representation of the performance of the electrical machine[1][2][3] drawn in terms of the locus of the machine’s input voltage and current.[4] The circle diagram can be drawn for alternators, synchronous motors, transformers, and induction motors.

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