# The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

### Right Answer is: 10 A

#### SOLUTION

When two resistors are connected in parallel, then-current is divided as according to current division rule

Let R1 = 20 Ω, R2 = 60 Ω, I = 40 A

${I_{R2}} = I\left( {\dfrac{{{R_1}}}{{{R_1} + {R_2}}}} \right)$

IR2 = I60Ω = 40 × (20 / 80)

I60Ω = 10 A

Scroll to Top