Find the value of ‘Req’ for the following circuit.
Find the value of ‘Req’ for the following circuit.
Right Answer is:
14.4 Ω
SOLUTION
2Ω + (6 || 3)Ω
6 Ω and 3 Ω resistors are in parallel, equivalent resistance = (6 × 3)/(6 + 3) = 2Ω
2Ω + 2Ω = 4Ω
1 Ω and 5 Ω resistors are in series, equivalent resistance = 1 + 5 = 6 Ω
6Ω || 4Ω = (6 × 4)/(6 + 4) = 2.4Ω
4 Ω, 2.4 Ω and 8 Ω resistors are in series.
Equivalent resistance (Req) = 4 + 2.4 + 8 = 14.4 Ω