61. The z-transform of a signal x(n) whose definition is given by \(X(z) = \sum_{n = 0}^{\infty} x(n)z^{-n}\) is known as ________
A. Unilateral z-transform
B. Bilateral z-transform
C. Rational z-transform
D. None of the mentioned
Answer: A
The z-transform of the x(n) whose definition exists in the range n = -∞ to +∞ is known as a bilateral or two-sided z-transform. But in the given question the value of n = 0 to +∞. So, such a z-transform is known as a Unilateral or one-sided z-transform.
62. For what kind of signals is one-sided z-transform unique?
A. All signals
B. Anti-causal signal
C. Causal signal
D. None of the mentioned
Answer: C
One-sided z-transform is unique only for causal signals because only these signals are zero for n<0.
63. What is the one sided z-transform X+(z) of the signal x(n) = {1,2,5,7,0,1}?
A. z2+2z+5+7z-1+z-3
B. 5+7z+z3
C. z-2+2z-1+5+7z+z3
D. 5+7z-1+z-3
Answer: D
Since the one sided z-transform is valid only for n> = 0, the z-transform of the given signal will be X+(z) = 5+7z-1+z-3.
64. What is the one-sided z-transform of x(n) = δ(n-k)?
A. z-k
B. zk
C. 0
D. 1
Answer: A
Since the signal x(n) = δ(n-k) is a causal signal i.e., it is defined for n>0 and x(n) = 1 at z = k
So, from the definition of one-sided z-transform X+(z) = z-k.
65. What is the one-sided z-transform of x(n) = δ(n+k)?
A. z-k
B. 0
C. zk
D. 1
Answer: B
Since the signal x(n) = δ(n+k) is an anti causal signal i.e., it is defined for n<0 and x(n) = 1 at z = -k. Since the one-sided z-transform is defined only for causal signal, in this case X+(z) = 0.
66. If X+(z) is the one sided z-transform of x(n), then what is the one sided z-transform of x(n-k)?
A. z-k X+(z)
B. zk X+(z-1)
C. z-k \([X^+(z)+\sum_{n = 1}^k x(-n)z^n]\); k>0
D. z-k \([X^+(z)+\sum_{n = 0}^k x(-n)z^n]\); k>0
Answer: C
From the definition of one sided z-transform we have,
68. If x(n) = an, then what is one sided z-transform of x(n+2)?
A. \(\frac{z^{-2}}{1-az^{-1}}\) + a-1z-1 + a-2
B. \(\frac{z^{-2}}{1-az^{-1}}\) – a-1z-1 + a-2
C. \(\frac{z^2}{1-az^{-1}}\) + a z + z2
D. \(\frac{z^2}{1+az^{-1}}\) – z2 – az
Answer: D
We will apply the time advance theorem with the value of k = 2.We obtain,
Z+{x(n+2)} = z2 X+(z)-x(0)z2-x(1)z
= >X1+(z) = \(\frac{z^2}{1+az^{-1}}\) – z2 – az.
69. If X+(z) is the one sided z-transform of the signal x(n), then
\(\lim_{n \rightarrow \infty} x(n) = \lim_{z\rightarrow 1}(z-1) X^+(z)\) is called Final value theorem.
A. True
B. False
Answer: A
In the above theorem, we are calculating the value of x(n) at infinity, so it is called as final value theorem.
70. The impulse response of a relaxed LTI system is h(n) = anu(n), |a|<1. What is the value of the step response of the system as n→∞?
A. \(\frac{1}{1+a}\)
B. \(\frac{1}{1-a}\)
C. \(\frac{a}{1+a}\)
D. \(\frac{a}{1-a}\)
Answer: B
The step response of the system is y(n) = x(n)*h(n) where x(n) = u(n)
On applying z-transform on both sides, we get
