Find the equivalent resistance, Req looking into the terminals of the following circuit as Indicated
Right Answer is:
14.4 Ω
SOLUTION
From the given figure resistance 6Ω & 3Ω are connected in parallel
= (6 × 3)/(6 + 3) = 2 Ω
Resistance 5Ω & 1Ω are connected in series
5Ω + 1Ω = 6Ω
Now resistance 2 Ω & 2 Ω are connected in series
= 2 + 2 =4Ω
Now resistance 4Ω and 6Ω are connected in parallel
= (4 × 6)/(4 + 6) = 2.4 Ω
Finally resistance 4Ω, 2.4Ω & 8Ω are connected in series
Req = 4 + 2.4 + 8
Req = 14.4Ω