Solve the following function $\int\limits_{ – \pi }^\pi {\sin (t)\sin (3t)dt = }$ Solve the following function $\int\limits_{ - \pi }^\pi {\sin (t)\sin (3t)dt = }$2π 0π/2 π Right Answer is: 0SOLUTION$\int\limits_{ – \pi }^\pi {\sin (t)\sin (3t)dt = }$ sin(t).sin(3t) Is even function therefore the limits becomes