In the diode circuit shown in the V1=10 sin 314.159 t V and VR= 5 V. Assume the diode to be ideal.

In the diode circuit shown in the V1=10 sin 314.159 t V and VR= 5 V. Assume the diode to be ideal. The maximum and minimum values of the output voltage (Vo) are, respectively.

Right Answer is: +5 V and −10V

SOLUTION

Given

Vin = 10 v

VR = 5 V

During the Positive half cycle, the diode is forward bias i.e Vin > Vr and the diode acts as a short circuit

Therefore the output voltage

Vout = Vin − Vr

Vout = 5 V (max Voltage)

During the negative half cycle, the diode is reversed biased and acts as an open circuit i.e Vin < Vr

Hence output voltage

Vout = Vin

Vout = −10 V (min voltage)

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