Find the equivalent capacitance, Ceq, at the terminals a-b of the circuit
Find the equivalent capacitance, Ceq, at the terminals a-b of the circuit
Right Answer is:
20 µF
SOLUTION
As shown in the figure the capacitor 5 µF and 20 µF are connected in series therefore its equivalent capacitance
= (5 × 20)/(5 + 20) = 4µF
Now capacitance 4µF, 6µF & 20 µF are connected in parallel
= 4 + 6 + 20 = 30 µF
At last 30 µF and 60 µF capacitors is connected in series
Ceq = (30 × 60)/(30 + 60) = 20 µF