The fully controlled thyristor converter in the figure is fed from a single-phase source. When the firing angle is 0°, the DC output voltage of the converter is 300 V. What will be the output voltage for a firing angle of 60°, assuming continuous conduction?
The fully controlled thyristor converter in the figure is fed from a single-phase source. When the firing angle is 0°, the DC output voltage of the converter is 300 V. What will be the output voltage for a firing angle of 60°, assuming continuous conduction?
Right Answer is:
150
SOLUTION
The output voltage of a fully controlled single-phase rectifier is given by
Vo = 2Vmcosα/π
Now at α = 0° Dc output is 300 V
300 =2Vmcos0°/π
300 =2Vm/π————(1)
For firing angle 60° the output voltage will be
Vo = 2Vmcos60°/π
Putting the value of 2Vm/π in equation 1 we get
Vo = 300cos60°
Vo = 150 V