The transistor is operating in the active region with VBE = 0.7 V. The value of collector current in mA is

A BJT biasing circuit is shown in the figure. The transistor is operating in the active region with VBE = 0.7 V. The value of collector current in mA is A BJT biasing circuit is shown in the figure. The transistor is operating in the active region with VBE = 0.7 V

Right Answer is:

2.817

SOLUTION

The given figure in the Question

A BJT biasing circuit is shown in the figure. The transistor is operating in the active region with VBE = 0.7 V

Given

VBE = 0.7 V

β = 100

Also

IE = (1 + β)IB

Applying KVL in the input loop

Vcc − (RB × IB) − VBE − [IE × RE] = 0

Vcc − (RB × IB) − VBE − [(1 + β)IB × RE] = 0

12 − (300 × IB) − 0.7 −101 × I= 0

11.3 − 402IB = 0

IB = 0.0281 mA

Collector current IC is given by

IC = β × IB

IC = 100 × 0.0281

IC = 2.81

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