# Resistance and Capacitance in Series MCQ [Free PDF] – Objective Question Answer for Resistance and Capacitance in Series Quiz

1. If in an alternating current circuit, resistance is 5 ohm, capacitive reactance is 12 ohm, what is the impedance?

A. 5 ohm
B. 10 ohm
C. 12 ohm
D. 13 ohm

R = 5Ω, XC = 12Ω

Z2 = R2+XC2

Substituting the values we get,

Z2  = 52 + 122

Z2  = 169

Z = 13 Ω.

2. If in an alternating current circuit, impedance is 26 ohm, capacitive reactance is 24 ohm, what is the resistance?

A. 25 ohm
B. 10 ohm
C. 12 ohm
D. 23 ohm

Z = 26Ω, XC = 24Ω

Z2 = R2+XC2

Substituting the values we get,

262  = R2 + 242

676 = R2 + 576

R2  = 100

R = 10 Ω.

3. If in an alternating current circuit, a capacitance of 30 µF is connected to a supply of 200V,50Hz. Find the current in the circuit.

A. 1.38 A
B. 1.89 A
C. 1.74 A
D. 0.89 A

XC = 1/(2πfC)= 106.1

I = V/XC

= 200/106.1 = 1.89 A.

4. If in an alternating current circuit, capacitance C is connected to a supply of 200V,50Hz. The current in the circuit is 1.89 A. Find the capacitance C.

A. 30 µF
B. 20 µF
C. 10 µF
D. 15 µF

XC = V/I

= 200/1.89 = 106.1 Ω.

XC = 1/(2πfC).

Substituting the values we get C = 30 µF.

5. In an ac circuit, the resistance of 5 ohms is connected with a capacitor having capacitive reactance of 12 ohms. A supply of 260 V is connected to the circuit. Calculate the current in the circuit.

A. 40 A
B. 10 A
C. 20 A
D. 30 A

Z2 = R2+XC2

Substituting the values we get

Z2  = 52 + 122

Z2  = 169

Z = 13 Ω.

I = V/Z = 260/13 = 20 A.

6. In an ac circuit, the resistance of 5 ohms is connected with a capacitor having capacitive reactance of 12 ohms. A supply of 260 V is connected to the circuit. Calculate the voltage across resistance.

A. 300 V
B. 200 V
C. 240 V
D. 100 V

Z2 = R2+XC2

Substituting the values we get

Z2  = 52 + 122

Z2  = 169

Z = 13 Ω.

I = V/Z = 260/13 = 20 A.

VR = iR = 20 × 5 = 100 V.

7. In an ac circuit, resistance 5 ohm is connected with a capacitor having capacitive reactance 12 ohm. A supply of 260 V is connected to the circuit. Calculate the voltage across a capacitor.

A. 300 V
B. 200 V
C. 240 V
D. 100 V

Z2 = R2+XC2

Substituting the values we get

Z2  = 52 + 122

Z2  = 169

Z = 13 Ω.

I = V/Z = 260/13 = 20 A.

VC = iXC = 20 × 12 = 240 V.

8. Find the total voltage applied in a series RLC circuit when i = 3mA, VL = 30V, VC = 18V, and R = 1000 ohms.

A. 3.95V
B. 51V
C. 32.67V
D. 6.67V

Total voltage = VR+VL+VC.

VR = 1000 × 3 × 10-3 = 3V.

Therefore, total voltage = 30+18+3 = 51V.

9. In an RLC circuit, which of the following is always used as a vector reference?

A. Voltage
B. Resistance
C. Impedance
D. Current

In an RLC circuit, the voltage is always used as a reference and according to the phase of the voltage, the phase of the other parameters is decided.

10. In an RLC circuit, the power factor is always ____________

A. Positive
B. Negative
C. Depends on the circuit
D. Zero