# Motor Acceleration Time MCQ [Free PDF] – Objective Question Answer for Motor Acceleration Time Quiz

1. Calculate the value of the angular acceleration of the motor using the given data: J = .01 kg-m2, load torque= 790 N-m, motor torque= 169 N-m.

Using the dynamic equation of motor

J*(angular acceleration) = Motor torque – Load torque:

.01*(angular acceleration) = 169-790=-621,

The motor will decelerate and will fail to start.

2. A 14-pole, 3-phase, 50 Hz induction motor is operating at a speed of 99 rpm. The frequency of the rotor current of the motor in Hz is __________

A. 39.5
B. 40
C. 38.45
D. 39.9

Given a number of poles = 14.

The supply frequency is 50 Hz.

The rotor speed is 699 rpm. Ns=120×f÷P

=120×50÷14 = 428.57 rpm.

S=Ns-Nr÷Ns

=428.57-99÷428.57=.769.

F2=sf=.769×50=38.45 Hz.

3. Calculate the phase angle of the sinusoidal waveform z(t)=18cos(1546πt+1900π÷76).

A. 25π÷39
B. 25π÷5
C. 25π÷1
D. π÷4

The sinusoidal waveform is generally expressed in the form of V=Vmsin(ωt+α)

where

Vm represents the peak value
Ω represents the angular frequency
α represents a phase difference.

4. Calculate the mass of the solid sphere having a moment of inertia 17 kgm2 and a radius of 4 cm.

A. 10624 kg
B. 10625 kg
C. 10628 kg
D. 10626 kg

The moment of inertia of the ball can be calculated using the formula

I=Σmiri2.

The moment of inertia of the ball and radius is given.

M=(17)÷(.04)2 = 10625 kg.

It depends upon the orientation of the rotational axis.

5. Calculate the moment of inertia of the thin spherical shell having a mass of 3 kg and a diameter of 66 cm.

A. .2156 kgm2
B. .2147 kgm2
C. .2138 kgm2
D. .2148 kgm2

The moment of inertia of the thin spherical shell can be calculated using the formula

I=mr2×.66.

The mass of the thin spherical shell and diameter is given

I=(3)×.66×(.33)2=.2156 kgm2.

It depends upon the orientation of the rotational axis.

6. Calculate the value of the time period if the frequency of the signal is 1 sec.

A. 1 sec
B. 2 sec
C. .5 sec
D. 1.5 sec

The time period is defined as the time after the signal repeats itself.

It is expressed in second. T = 1÷F=1÷1=1 sec.

7. The slope of the V-I curve is 270°. Calculate the value of resistance.

A. 112 Ω
B. 178 Ω
C. infinite Ω
D. 187 Ω

The slope of the V-I curve is resistance. The slope given is 270° so R=tan(270°)=infinite Ω. It behaves as an open circuit.

8. The slope of the V-I curve is 23.56°. Calculate the value of resistance. Assume the relationship between voltage and current is a straight line.

A. .464 Ω
B. .436 Ω
C. .443 Ω
D. .463 Ω

The slope of the V-I curve is resistance.

The slope given is 23.56° so R=tan(23.56°)=.436 Ω.

The slope of the I-V curve is reciprocal to resistance.

9. Calculate the reactive power in a 23 Ω resistor.

A. 45 VAR
B. 10 VAR
C. 245 VAR
D. 0 VAR

The resistor is a linear element. It only absorbs real power and dissipates it in the form of heat.

The voltage and current are in the same phase in the case of the resistor so the angle between V & I is 90°.

Q = VIsin0° = 0 VAR.

10. A 3-phase induction motor runs at almost 50 rpm at no load and 25 rpm at full load when supplied with power from a 50 Hz, 3-phase supply. What is the corresponding speed of the rotor field with respect to the rotor?

A. 25 revolution per minute
B. 20 revolution per minute
C. 10 revolution per minute
D. 30 revolution per minute

Supply frequency=50 Hz.
No-load speed of motor= 50 rpm.
Full load speed of the motor = 25 rpm.

Since the no-load speed of the motor is almost 50 rpm, hence synchronous speed is near to 50 rpm.

Speed of rotor field=50 rpm. Speed of rotor field with respect to rotor

= 50-25 = 25 rpm.

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