A. 2δ(n)+4δ(n-1)+3δ(n-3)
B. 2δ(n+1)+4δ(n)+3δ(n-2)
C. 2δ(n)+4δ(n-1)+3δ(n-2)
D. None of the mentioned
Answer: B
We know that, x(n)δ(n-k)=x(k)δ(n-k)
x(-1)=2=2δ(n+1)
x(0)=4=4δ(n)
x(2)=3=3δ(n-2)
Therefore, x(n)= 2δ(n+1)+4δ(n)+3δ(n-2).
22. The formula y(n)=\(\sum_{k=-\infty}^{\infty}x(k)h(n-k)\) that gives the response y(n) of the LTI system as the function of the input signal x(n) and the unit sample response h(n) is known as ______________
A. Convolution sum
B. Convolution product
C. Convolution Difference
D. None of the mentioned
Answer: A
The input x(n) is convoluted with the impulse response h(n) to yield the output y(n). As we are summing the different values, we call it a Convolution sum.
23. What is the order of the four operations that are needed to be done on h(k) in order to convolute x(k) and h(k)?
A. Step-1:Folding
B. Step-2:Multiplication with x(k)
C. Step-3:Shifting
D. All of the above
Answer: D
The four operations that are needed to be done on h(k) in order to convolute x(k) and h(k) is
Step-1:Folding
Step-2:Multiplication with x(k)
Step-3:Shifting
Step-4:Summation
First, the signal h(k) is folded to get h(-k). Then it is shifted by n to get h(n-k). Then it is multiplied by x(k) and then summed over -∞ to ∞.
24. The impulse response of a LTI system is h(n)={1,1,1}. What is the response of the signal to the input x(n)={1,2,3}?
A. {1,3,6,3,1}
B. {1,2,3,2,1}
C. {1,3,6,5,3}
D. {1,1,1,0,0}
Answer: C
Let y(n)=x(n) × h(n)(‘ × ’ symbol indicates convolution symbol)
From the formula of convolution we get,
y(0)=x(0)h(0)=1.1=1
y(1)=x(0)h(1)+x(1)h(0)=1.1+2.1=3
y(2)=x(0)h(2)+x(1)h(1)+x(2)h(0)=1.1+2.1+3.1=6
y(3)=x(1)h(2)+x(2)h(1)=2.1+3.1=5
y(4)=x(2)h(2)=3.1=3
Therefore, y(n)=x(n) × h(n)={1,3,6,5,3}.
25. Determine the output y(n) of a LTI system with impulse response h(n)=anu(n), |a|<1 with the input sequence x(n)=u(n).
A. \(\frac{1-a^{n+1}}{1-a}\)
B. \(\frac{1-a^{n-1}}{1-a}\)
C. \(\frac{1+a^{n+1}}{1+a}\)
D. None of the mentioned
Answer: A
Fold the signal x(n) and shift it by one unit at a time and sum as follows
y(0)=x(0)h(0)=1
According to the properties of convolution, the Convolution of three signals obeys the Associative property.
x(n) × (h1(n) × h2(n))=(x(n) × h1(n)) × h2(n).
27. Determine the impulse response for the cascade of two LTI systems having impulse responses h1(n)=\((\frac{1}{2})^2\) u(n) and h2(n)=\((\frac{1}{4})^2\) u(n).
A. \((\frac{1}{2})^n[2-(\frac{1}{2})^n]\), n<0
B. \((\frac{1}{2})^n[2-(\frac{1}{2})^n]\), n>0
C. \((\frac{1}{2})^n[2+(\frac{1}{2})^n]\), n<0
D. \((\frac{1}{2})^n[2+(\frac{1}{2})^n]\), n>0
Answer: B
Let h2(n) be shifted and folded.
so, h(k)=h1(n) × h2(n)=\(\sum_{k=-\infty}^{\infty} h_1 (k)h_2 (n-k)\)
For k<0, h1(n)= h2(n)=0 since the unit step function is defined only on the right hand side.
According to the properties of the convolution, convolution exhibits the distributive property.
x(n) × [h1(n)+h2(n)]=x(n) × h1(n)+x(n) × h2(n).
29. An LTI system is said to be causal if and only if?
A. Impulse response is non-zero for positive values of n
B. Impulse response is zero for positive values of n
C. Impulse response is non-zero for negative values of n
D. Impulse response is zero for negative values of n
Answer: D
Let us consider a LTI system having an output at time n=n0 given by the convolution formula
y(n)=\(\sum_{k=-{\infty}}^{\infty}h(k)x(n_0-k)\)
As per the definition of the causality, the output should depend only on the present and past values of the input. So, the coefficients of the terms x(n0+1), x(n0+2)…. should be equal to zero.