DC Shunt Motor MCQ || DC Shunt Motor Questions and Answers

21 . How speed of the DC shunt motor can be increased?

  1. Decreasing the field current
  2. Increasing the field current
  3. Decreasing the load current
  4. Increasing the armature current

Answer: 1. Decreasing the field current

Explanation:

  • In the field control method of the shunt motor, a variable resistance is connected in series with the shunt field and is adjusted to change the field current as required.
  • The speed is inversely proportional to the flux when the applied voltage is not changed and the back emf can be considered constant. Thus, increasing the resistance in the shunt field decreases the shunt field current, decreases the flux, and increases the speed.
  • In the same way. decreasing the resistance in the shunt field circuit increases the shunt field current, increases the flux and decreases the speed.

 

22. For some percentage increase in the torque, which DC motor will have the high percentage increase of input current?

  1. Series motor
  2. Shunt motor
  3. Cumulative compound motor
  4. Separately excited motor

Answer: 2. Shunt motor

Explanation:

  • The source current supplied to the DC shunt motor is divided into two parts, field current, and armature current.
  • The field current is kept constant for constant flux generation for a given workload.
  • So, the torque depends only on armature current where field current remains constant.
  • Hence, to produce the same torque as that in a series motor, more amount of current is to be supplied through the source compared to the series.
  • Therefore, the shunt motor will have the highest percentage increase in input current for a given percentage increase in torque.

 

23. For some percentage increase in the torque, which DC motor will have the least percentage increase of input current?

  1. Series motor
  2. Shunt motor
  3. Cumulative compound motor
  4. Separately excited motor

Answer: 2. Shunt motor

Explanation:

  • In the series motor, both field and armature winding carry the same current from the source as connected in the series.
  • Now, torque is directly proportional to the product of current in field and armature windings, for a given source current the torque produced is square of this current.
  • Hence, for a great change in torque, the current change is less.

 

24. If load torque varies with the square of the speed and the terminal voltage of DC shunt motor is halved, then the speed:

  1. Will be doubled
  2. Becomes triple
  3. Will be halved
  4. Remains constant

Answer:1. Will be doubled

Explanation:

Speed of DC shunt motor is given by,

$N \propto \frac{{{E_b}}}{\phi } \propto \frac{{V – {I_a}{R_a}}}{\phi }$

But generally, Ra term is small, hence this term is neglected.

⇒ E ∝ V

Now the speed is,

$\Rightarrow N \propto \frac{{{E_b}}}{\phi } \propto \frac{V}{\phi }$

From data, as V is half, ϕ becomes half, such that speed becomes constant. Also given that,

T ∝ N2, T ∝ φIa

Since speed is not changed even V is half, the torque also remains unchanged.

Hence to get constant torque with field flux fallen to half, armature current has to be doubled.

 

25. Which of the following applications use shunt DC motors?

  1. Milling machines
  2. Hoists and elevators
  3. Elevators
  4. Electric locomotives

Answer: 1. Milling machines

Explanation:

  • DC Shunt Motor is an almost constant speed motor and its torque varies nearly as the current.
  • Hence, it is used for driving constant speed line shafts, lathes, constant speed head centrifugal pumps, fans,  woodworking machines, reciprocating pumps, laundry washing machines, milling machines, grinders, small printing presses, paper making machines, metal cutting machines, etc.

 

26. Practical reason behind speed of DC shunt motor is proportional to back emf only is ____________

  1. Back emf is equal to armature drop
  2. Flux is proportional to field current
  3. Flux is proportional to armature current
  4. Flux is practically constant in DC shunt motors

Answer: 4. Flux is practically constant in DC shunt motors

Explanation:

In DC shunt Motor the field winding is connected in parallel to the armature winding and the supply.

N ∝ Eb/φ.

As the shunt field resistance is constant, the shunt field current is constant. Accordingly, the flux per pole is practically constant. The back emf is also practically constant. Hence, by speed relation, it is seen that the speed of a DC shunt motor is constant.

The speed of a DC shunt motor is dependent on back emf because the flux is practically constant in a DC shunt motor.

 

27. DC Shunt Motor has a disadvantage __________

  1. Constant speed
  2. Less expensive
  3. Not suitable for rapidly changing loads
  4. Cannot be determined

Answer:3. Not suitable for rapidly changing loads

Explanation:

DC shunt motor should be started with no-load and never start with heavy load because

  • The change in field flux is very less due to the load, so we can assume the flux to be constant. So flux (ɸ) is constant, and the speed is directly proportional to back emf (E.
  • Now Eb is also constant, so eventually, speed is also constant. But in practice, there is a slight decrease in speed from no-load to a full load of DC shunt motor.
  • This is why DC shunt motors are known as constant-speed motors.

In DC shunt motor, due to shunt characteristics, speed variation depends not only upon the controlling resistance but on the load current also. This double dependence makes it impossible to keep the speed sensibly constant on a rapidly changing load.

 

28. Which of the following motors is used for centrifugal pumps?

  1. Series Motors
  2. Shunt Motor
  3. Induction Motor
  4. Either Series or Shunt

Answer:2. Shunt Motor

Explanation:

DC shunt motor is an almost constant speed motor. Hence it is used for driving constant speed line shafts, lathes, centrifugal pumps, small printing presses, paper making machines, etc.

 

29. A dc shunt motor operating in a linear region of magnetizing characteristics runs at 1500 rpm with a voltage rated over the entire portion of the armature in a linear region of magnetizing characteristics. If the applied voltage is reduced by 50%, what will be the speed of the motor?

  1. 750 rpm
  2. 2500 rpm
  3. 3000 rpm
  4. 1500 rpm

Answer:4. 1500 rpm

Explanation:

Let applied voltage =  V

Reduced applied voltage =  V / 2

No-load speed = 1500 rpm

As the speed is constant irrespective of voltage variation, the speed will be 1500 rpm at reduced voltage.

 

30.  A 250 V dc motor has an armature resistance of 0.5 Ω. It is drawing an armature current of 25 A, driving a certain load. Calculate the induced emf in the motor under these conditions.

  1. 180.5 V
  2. 237.5 V
  3. 192.5 V
  4. 625 V

Answer:2. 237.5 V

Explanation:

Given that, voltage (V) = 250 V

Armature resistance (R = 0.5 Ω

Shunt current is neglected.

Armature current (I = (IL) = 25 A

Back emf (E = V – IaRa = 250 – 25 × 0.5 = 237.5 V

 

31. Which of the following is NOT an application of shunt motor?

  1. Electric locomotive
  2. Centrifugal pumps
  3. For driving constant speed line shafting lathes
  4. Machine tools

Answer:1. Electric locomotive

Explanation:

  • A shunt-wound motor is an almost constant speed motor and its torque varies nearly as the current.
  • Hence, it is used for driving constant speed line shafts, lathes, constant speed head centrifugal pumps, fans woodworking machines, reciprocating pumps, laundry washing machines, milling machines, grinders, small printing presses, paper making machines, metal cutting machines, etc.

From the given option electric locomotive is not an application of shunt motor, so option 1 is the correct answer.

 

32. A 240v dc shunt motor with an armature resistance of 0.5 has a full load current of 40A. Find out the ratio of the stalling torque to the full load torque when resistance of 1 ohm is connected in series with the armature.

  1. 4
  2. 6
  3. 12
  4. None

Answer:1. 4

Explanation:

Stalling torque is the torque at which speed would fall to zero.

With N = 0

Eb = V − IaRa

240 − Ia(1.5) = 0

Ia = 160 A

T2/T1 = I2/I1

T2/T1 = 160/40 = 4

 

33. A 220 V dc shunt motor is running at 500 rpm when the armature current is 50 A. The value of armature resistance is 0.2 ohm. The speed of the motor at the double torque will be

  1. 250 rpm
  2. 500 rpm
  3. 1000 rpm
  4. 476 rpm

Answer:4. 476 rpm

Explanation:

Performance eqn of DC shunt motors are

Eb = Vt – IaRa

or, Eb = Kaϕω       _ _ _ _ _ (1)

and τ = KaϕIa       _ _ _ _ _ (2)

Eb1 = 220 – 50 × 0.2

= 220 – 10 = 210 V

Since Torque is double i.e., armature current is doubled

i.e., Ia2 = 2 × Ia1 = 2 × 50 = 100 A

∴ Eb2 = 220 – 100 × 0.2

= 200 V

Eb2/Eb1 = N2/N1

N2 = 500 × 200/210 = 476 RPM

 

34. When speeds below normal are required in DC shunt Motor the best-suited method is ______

  1. Field Resistance control
  2. Armature Resistance control
  3. Armature Voltage Control
  4. Shunt Resistance Control

Answer:2. Armature Resistance control

Explanation:

An armature resistance control method is very simple and usually employed when speeds below normal are required. But this method suffers from the drawback that the motor speed changes with every change in load on the machine.

It is because the speed variation does not depend only upon the controlling resistance but it also depends upon load current. Because of this reason constant speed cannot be obtained in case of rapidly changing loads.

 

35. DC shunt Motor is used in applications where adjustable speed in the range of _______ is required.

  1. 2:1
  2. 3:5
  3. 5:3
  4. 1:2

Answer:1. 2:1

Explanation:

DC shunt motor is a constant speed motor

  • It is used in applications where constant speed is required.
  • It is used in applications where adjustable speed in the range of 2:1, along with a medium starting torque is required.
  • It is used in lathe machines, centrifugal pumps, fans, and blowers, machine tools like wood working machines, reciprocating pumps, spinning and weaving machines etc.

Scroll to Top