21 . How speed of the DC shunt motor can be increased?
Decreasing the field current
Increasing the field current
Decreasing the load current
Increasing the armature current
Answer: 1. Decreasing the field current
Explanation:
In the field control method of the shunt motor, a variable resistance is connected in series with the shunt field and is adjusted to change the field current as required.
The speed is inversely proportional to the flux when the applied voltage is not changed and the back emf can be considered constant. Thus, increasing the resistance in the shunt field decreases the shunt field current, decreases the flux, and increases the speed.
In the same way. decreasing the resistance in the shunt field circuit increases the shunt field current, increases the flux and decreases the speed.
22. For some percentage increase in the torque, which DC motor will have the high percentage increase of input current?
Series motor
Shunt motor
Cumulative compound motor
Separately excited motor
Answer: 2. Shunt motor
Explanation:
The source current supplied to the DC shunt motor is divided into two parts, field current, and armature current.
The field current is kept constant for constant flux generation for a given workload.
So, the torque depends only on armature current where field current remains constant.
Hence, to produce the same torque as that in a series motor, more amount of current is to be supplied through the source compared to the series.
Therefore, the shunt motor will have the highest percentage increase in input current for a given percentage increase in torque.
23. For some percentage increase in the torque, which DC motor will have the least percentage increase of input current?
Series motor
Shunt motor
Cumulative compound motor
Separately excited motor
Answer: 2. Shunt motor
Explanation:
In the series motor, both field and armature winding carry the same current from the source as connected in the series.
Now, torque is directly proportional to the product of current in field and armature windings, for a given source current the torque produced is square of this current.
Hence, for a great change in torque, the current change is less.
24. If load torque varies with the square of the speed and the terminal voltage of DC shunt motor is halved, then the speed:
But generally, Ra term is small, hence this term is neglected.
⇒ E ∝ V
Now the speed is,
$\Rightarrow N \propto \frac{{{E_b}}}{\phi } \propto \frac{V}{\phi }$
From data, as V is half, ϕ becomes half, such that speed becomes constant. Also given that,
T ∝ N2, T ∝ φIa
Since speed is not changed even V is half, the torque also remains unchanged.
Hence to get constant torque with field flux fallen to half, armature current has to be doubled.
25. Which of the following applications use shunt DC motors?
Milling machines
Hoists and elevators
Elevators
Electric locomotives
Answer: 1. Milling machines
Explanation:
DC Shunt Motor is an almost constant speed motor and its torque varies nearly as the current.
Hence, it is used for driving constant speed line shafts, lathes, constant speed head centrifugal pumps, fans, woodworking machines, reciprocating pumps, laundry washing machines, milling machines, grinders, small printing presses, paper making machines, metal cutting machines, etc.
26. Practical reason behind speed of DC shunt motor is proportional to back emf only is ____________
Back emf is equal to armature drop
Flux is proportional to field current
Flux is proportional to armature current
Flux is practically constant in DC shunt motors
Answer: 4. Flux is practically constant in DC shunt motors
Explanation:
In DC shunt Motor the field winding is connected in parallel to the armature winding and the supply.
N ∝ Eb/φ.
As the shunt field resistance is constant, the shunt field current is constant. Accordingly, the flux per pole is practically constant. The back emf is also practically constant. Hence, by speed relation, it is seen that the speed of a DC shunt motor is constant.
The speed of a DC shunt motor is dependent on back emf because the flux is practically constant in a DC shunt motor.
27. DC Shunt Motor has a disadvantage __________
Constant speed
Less expensive
Not suitable for rapidly changing loads
Cannot be determined
Answer:3. Not suitable for rapidly changing loads
Explanation:
DC shunt motor should be started with no-load and never start with heavy load because
The change in field flux is very less due to the load, so we can assume the flux to be constant. So flux (ɸ) is constant, and the speed is directly proportional to back emf (E.
Now Eb is also constant, so eventually, speed is also constant. But in practice, there is a slight decrease in speed from no-load to a full load of DC shunt motor.
This is why DC shunt motors are known as constant-speed motors.
In DC shunt motor, due to shunt characteristics, speed variation depends not only upon the controlling resistance but on the load current also. This double dependence makes it impossible to keep the speed sensibly constant on a rapidly changing load.
28. Which of the following motors is used for centrifugal pumps?
Series Motors
Shunt Motor
Induction Motor
Either Series or Shunt
Answer:2. Shunt Motor
Explanation:
DC shunt motor is an almost constant speed motor. Hence it is used for driving constant speed line shafts, lathes, centrifugal pumps, small printing presses, paper making machines, etc.
29. A dc shunt motor operating in a linear region of magnetizing characteristics runs at 1500 rpm with a voltage rated over the entire portion of the armature in a linear region of magnetizing characteristics. If the applied voltage is reduced by 50%, what will be the speed of the motor?
750 rpm
2500 rpm
3000 rpm
1500 rpm
Answer:4. 1500 rpm
Explanation:
Let applied voltage = V
Reduced applied voltage = V / 2
No-load speed = 1500 rpm
As the speed is constant irrespective of voltage variation, the speed will be 1500 rpm at reduced voltage.
30. A 250 V dc motor has an armature resistance of 0.5 Ω. It is drawing an armature current of 25 A, driving a certain load. Calculate the induced emf in the motor under these conditions.
180.5 V
237.5 V
192.5 V
625 V
Answer:2. 237.5 V
Explanation:
Given that, voltage (V) = 250 V
Armature resistance (R = 0.5 Ω
Shunt current is neglected.
Armature current (I = (IL) = 25 A
Back emf (E = V – IaRa = 250 – 25 × 0.5 = 237.5 V
31. Which of the following is NOT an application of shunt motor?
Electric locomotive
Centrifugal pumps
For driving constant speed line shafting lathes
Machine tools
Answer:1. Electric locomotive
Explanation:
A shunt-wound motor is an almost constant speed motor and its torque varies nearly as the current.
Hence, it is used for driving constant speed line shafts, lathes, constant speed head centrifugal pumps, fans woodworking machines, reciprocating pumps, laundry washing machines, milling machines, grinders, small printing presses, paper making machines, metal cutting machines, etc.
From the given option electric locomotive is not an application of shunt motor, so option 1 is the correct answer.
32. A 240v dc shunt motor with an armature resistance of 0.5 has a full load current of 40A. Find out the ratio of the stalling torque to the full load torque when resistance of 1 ohm is connected in series with the armature.
4
6
12
None
Answer:1. 4
Explanation:
Stalling torque is the torque at which speed would fall to zero.
With N = 0
Eb = V − IaRa
240 − Ia(1.5) = 0
Ia = 160 A
T2/T1 = I2/I1
T2/T1 = 160/40 = 4
33. A 220 V dc shunt motor is running at 500 rpm when the armature current is 50 A. The value of armature resistance is 0.2 ohm. The speed of the motor at the double torque will be
250 rpm
500 rpm
1000 rpm
476 rpm
Answer:4. 476 rpm
Explanation:
Performance eqn of DC shunt motors are
Eb = Vt – IaRa
or, Eb = Kaϕω _ _ _ _ _ (1)
and τ = KaϕIa _ _ _ _ _ (2)
Eb1 = 220 – 50 × 0.2
= 220 – 10 = 210 V
Since Torque is double i.e., armature current is doubled
i.e., Ia2 = 2 × Ia1 = 2 × 50 = 100 A
∴ Eb2 = 220 – 100 × 0.2
= 200 V
Eb2/Eb1 = N2/N1
N2 = 500 × 200/210 = 476 RPM
34. When speeds below normal are required in DC shunt Motor the best-suited method is ______
Field Resistance control
Armature Resistance control
Armature Voltage Control
Shunt Resistance Control
Answer:2. Armature Resistance control
Explanation:
An armature resistance control method is very simple and usually employed when speeds below normal are required. But this method suffers from the drawback that the motor speed changes with every change in load on the machine.
It is because the speed variation does not depend only upon the controlling resistance but it also depends upon load current. Because of this reason constant speed cannot be obtained in case of rapidly changing loads.
35. DC shunt Motor is used in applications where adjustable speed in the range of _______ is required.
2:1
3:5
5:3
1:2
Answer:1. 2:1
Explanation:
DC shunt motor is a constant speed motor
It is used in applications where constant speed is required.
It is used in applications where adjustable speed in the range of 2:1, along with a medium starting torque is required.
It is used in lathe machines, centrifugal pumps, fans, and blowers, machine tools like wood working machines, reciprocating pumps, spinning and weaving machines etc.